Answer:
The wind pushed the plane 
miles in the direction of 
East of North with respect to the destination point.
Step-by-step explanation:
Let origin, O, br the starting point and point D be the destination at 250 miles at a bearing of 20° E of S, but due to wind let D' be the actual position of the plane at 230 miles away from the starting point in the direction of 35° E of South as shown in the figure.
So, we have |OD|=250 miles and |OD'|=230 miles.
Vector 
is the displacement vector of the plane pushed by the wind.
From figure, the magnitude of the required displacement vector is
and the direction is 
east of north as shown in the figure,
From the figure,
miles
Again, 
miles
Now, from equations (i) and (ii), we have
miles, and
Hence, the wind pushed the plane miles in the direction of E astof North with respect to the destination point.
Answer:
Step-by-step explanation:
A function has a root only if cuts the x axis .
If it cuts once it means it has one real root, if twice then two roots and so on .
Here in the graph of G(x) shown ,it never crosses the x axis so we can say that there is no real root of the given function G(x).
It means the option A which states G(x) has zero roots is correct.
Refer to the attachments...
Hello from MrBillDoesMath!
Answer:
@ = pi/3 (or 60 degrees) or @ = 7 pi/3 (or 420 degrees)
Discussion:
Let "@' denote the angle "theta". We are asked to find @ in the interval [0, 4 pi)
where
4cos(@) - 2 = 0. Adding 2 to both sides
4 cos(@) - 2 +2 = 2 =>
4 cos(@) = 2 Divide both sides by 4
cos(@) = 2/4 = 0.5
This implies that @ = pi/3 (or 60 degrees) or @ = (pi/3 + 2pi) = 7 pi/3 (or 420 degrees)
Thank you,
MrB
