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jek_recluse [69]
3 years ago
12

TRIGNONMETRY

Mathematics
1 answer:
pishuonlain [190]3 years ago
6 0

Answer:

i like ur pp

Step-by-step explanation:

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Help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
USPshnik [31]

Answer:

The given information tells us that AFD is either an equilateral or isosceles triangle.  We can see by the diagram that it is not equilateral, so the correct answer here would be the second one, "Isosceles".

7 0
3 years ago
Rodney bought a 25-pound bag of dog food.His dog at 10 2/5 pounds of food in the first month and 10 4/5 pounds of the food in th
wlad13 [49]
10 4/5+ 10 2/5= 20 1/5 
25- 20 1/5 = 4 4/5 pounds of dog food is left.
7 0
3 years ago
Read 2 more answers
What is the equation of the line that passes through the points (-3,5) (6,8)
Ratling [72]

(\stackrel{x_1}{-3}~,~\stackrel{y_1}{5})\qquad (\stackrel{x_2}{6}~,~\stackrel{y_2}{8}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{8}-\stackrel{y1}{5}}}{\underset{run} {\underset{x_2}{6}-\underset{x_1}{(-3)}}}\implies \cfrac{3}{6+3}\implies \cfrac{3}{9}\implies \cfrac{1}{3}

\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{5}=\stackrel{m}{\cfrac{1}{3}}(x-\stackrel{x_1}{(-3)}) \\\\\\ y-5=\cfrac{1}{3}(x+3)\implies y-5=\cfrac{1}{3}x+1\implies y=\cfrac{1}{3}x+6

6 0
2 years ago
The temperature during a winter day was less than –3 degrees Fahrenheit. Yuri wants to write an inequality for the temperature d
sveticcg [70]
We are given that the temperature is less than (<) -3 degrees Fahrenheit.
Since the temperature is represented by the variable "t", then t is less than -3.

So, the inequality which best describes the situation is:
t < -3 

Checking the choices, we will find that the correct choice is: 
<span>C: t < -3</span>
8 0
3 years ago
Read 2 more answers
The Toylot company makes an electric train with a motor that it claims will draw an average of only 0.8 ampere (A) under a norma
Igoryamba

Answer:

Step-by-step explanation:

Given that population average is 0.8 ampere

Sample size = 9

Sample mean x bar = 1.34 A

Sample std dev s = 0.48

H_o: x bar =0.8\\H_a: x bar >0.8

(one tailed test)

Mean difference - 1.34-0.8 =0.54

Std error = \frac{s}{\sqrt{n} } =0.16

t test can be used since sigma is not known and sample size small

t statistic = mean diff/std error = 3.5

df = 8

p value = 0.00404

5 0
3 years ago
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