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3 years ago

10

Solve the quadratic equations below using the factorization method.

1 answer:

liubo4ka [24]3 years ago

4 0

Answer: omg this is hard

Step-by-step explanation:

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Could somebody please help me I dont understand how to do this problem

forsale [732]

So a triangle has a total of 180 degrees
107 + 2x-5 +x = 180
solve for x
112 + 3x = 180
-112 -112
3x = 68
x = 22.6667 degrees

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3 years ago

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Gennadij [26K]

A is correct
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Express each number as a product of its prime factor of 39

vitfil [10]

If you just mean the product of the prime factors of 39 then this is the answer

39 = 3 x 13

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3 years ago

How do I factor this polynomial? q^2-121

Tresset [83]

$q^2-121 =q^2-11^2=(q-11)(q+11)\\ \\ \\a^2-b^2 =(a-b)(a+b)$

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3 years ago

(x-1)^2+(2-x)^2-3(x-5)*(x-5)

Natali5045456 [20]

Answer:

$-x^2+24x-70$

Step-by-step explanation:

$(x-1)^2+(2-x)^2-3(x-5)*(x-5)\\=> (x - 1)^2 + (2 - x)^2 - 3(x - 5)^2\\=> x^2 - 2x + 1 + 4 - 4x + x^2 - 3(x - 5)^2\\=> x^2 - 2x + 5 - 4x + x^2 - 3(x - 5)^2\\=> x^2 - 6x + 5 + x^2 - 3(x - 5)^2\\=> 2x^2 - 6x+5 - 3(x - 5)^2\\=> 2x^2 - 6x+5 - 3(x^2 - 10x + 25)\\=> 2x^2 - 6x+5 - 3x^2+30x-75\\=> -x^2 - 6x + 5 + 30x - 75\\=> -x^2 + 24x + 5-75\\=> -x^2+24x-70$

Formula used =

$(a-b)^2 = a^2+ 2ab + b^2$

8 0

3 years ago