Can someone please help me with this question?

Nadusha1986 [10]

The value of the variable x will be 37°. Then the measure of the angle ∠QNP will be 105°.

<h3>What is an angle?</h3>

The angle is the distance between the intersecting lines or surfaces. The angle is also expressed in degrees. The angle is 360 degrees for one complete spin.

Supplementary angle - Two angles are said to be supplementary angles if their sum is 180 degrees.

The measure of angles ∠MNQ = (2x + 1)° and ∠QNP = (3x - 6)°.

Then the value of x will be

We know that the angles ∠MNQ and ∠QNP are supplementary angles. Then the value of the variable x will be

∠MNQ + ∠QNP = 180°

(2x + 1)° + (3x - 6)° = 180°

5x - 5° = 180°

5x = 185°

x = 37°

Then the measure of the angle ∠QNP will be

∠QNP = [3(37) - 6]°

∠QNP = 111° - 6°

∠QNP = 105°

The value of the variable x will be 37°. Then the measure of the angle ∠QNP will be 105°.

More about the angled link is given below.

brainly.com/question/15767203

#SPJ1

4 0

2 years ago

What is the volume of a square pyramid with base edges of 60 inches and a height of 10 inches?

vichka [17]

Answer:

The volume is $12000 in^3$

Step-by-step explanation:

From the question ,

$L= 60\:in.$ and $H=10\:in.$

The volume of a pyramid is given as

$V=\frac{1}{3} \times area\:of\:the\:base \times height$

From the question, the base of the pyramid is a square.

Hence base area is given by $L^{2}$

This implies that the volume of the pyramid is

$=\frac{1}{3} \times L^{2}\times H$

$=\frac{1}{3}\times 60^{2} \times 10$

$=\frac{36000}{3}$

$=12000 in^3$

6 0

3 years ago

How to find imaginary zeros anf real zeros of F(x)=-4x^5-8x^3+12x

Fofino [41]

Answer:

$x=\{0, -1, 1, -i\sqrt{3}, i\sqrt{3}\}$

Step-by-step explanation:

We are given the function:

$f(x)=-4x^5-8x^3+12x$

And we want to finds its zeros.

Therefore:

$0=-4x^5-8x^3+12x$

Firstly, we can divide everything by -4:

$0=x^5+2x^3-3x$

Factor out an x:

$0=x(x^4+2x^2-3)$

This is in quadratic form. For simplicity, we can let:

$u=x^2$

Then by substitution:

$0=x(u^2+2u-3)$

Factor:

$0=x(u+3)(u-1)$

Substitute back:

$0=x(x^2+3)(x^2-1)$

By the Zero Product Property:

$x=0\text{ and } x^2+3=0\text{ and } x^2-1=0$

Solving for each case:

$x=0\text{ and } x=\pm\sqrt{-3}\text{ and } x=\pm\sqrt{1}$

Therefore, our real and complex zeros are:

$x=\{0, -1, 1, -i\sqrt{3}, i\sqrt{3}\}$

4 0

2 years ago

Find the value of X and y .If order pair (X,y)=(6,7)

Darina [25.2K]

Answer:

x=6,y=7

Step-by-step explanation:

In a coordinate pair it is assumed that the first number is x, and the 2nd is y.

7 0

3 years ago

What is the formula for the area of a triangle?

SashulF [63]

The formula to find the area of a triangle is :

1/2 base*height

For instance:

base=4 cm

height=5cm

area of traingle=1/2*b*h

 =1/2*4*5

 =10cm^2

Hope it helps...

Good luck on your assignment

6 0

3 years ago