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2 years ago

Help!! please, i will give brainliest

Mathematics

2 answers:

Alenkasestr [34]2 years ago

8 0

It's D
i hope this helped!

saw5 [17]2 years ago

5 0

It’s D :)
I really hope that helped

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19 students were surveyed on the number of hours of Netflix they watched last week.

Sonbull [250]

Answer:

Solution given:

lowest =0

highest=11

the range in hours spent watching Netflix=

highest-lowest =11-0=

Range is 11.

3 0

3 years ago

Read 2 more answers

Based on the survey results from 300 selected students in the Burbank School District (BSD), the 98% confidence interval used to

Pavlova-9 [17]

Answer:

follows are the solution to this question:

Step-by-step explanation:

Please find the correct question in the attached file:

The formula for calculating the Confidence interval of proportion:

$\to CI=\hat{p} \pm Z_{\frac{\alpha}{2}} \sqrt{\frac{\hat{p}(1-\hat{p})}{n}}\\\\\to \hat{p}=\frac{\text{lower limit +upper limit}}{2}\\$

$=\frac{0.48+0.60}{2}\\\\=\frac{1.08}{2}\\\\=0.54$

The number of learners with access to working at home on a computer:

$= 0.54 \times 300 \\\\=162$

Lower limit =0.48

upper limit = 0.60

$\to margin \ error = \frac{\text{upper limit - lower limit}}{2}\\$

$=\frac{0.60-0.48}{2}\\\\=\frac{0.12}{2}\\\\= 0.06$

5 0

3 years ago

A store owner determined 80% of customers bought a drink and 30% of customers bought a snack. If the store sold 120 snacks that

NISA [10]

The answer is 196 if i stand corrected

8 0

3 years ago

Write the two consecutive integers between which the given rational lies

meriva

Answer:

a) -1, 0

b) -5, -4

c) 2, 3

d) -8, -7

Step-by-step explanation:

4 0

3 years ago

A container contains 12 diesel engines. The company chooses 5 engines at random, and will not ship the container if any of the

Rufina [12.5K]

Answer: $\frac{^{10}C_5}{^{12}C_5}$

Step-by-step explanation:

Given a total of 12 diesel engines

out of which 2 are defective

Company have to choose 5 good engines to ship.

Therefore no of ways in good engines are selected is $^{10}C_5$

no of ways in which any 5 engines are selected from a total of 12 engines is

$^{12}C_5$

Therefore the required probability = $\frac{^{10}C_5}{^{12}C_5}$

= $\frac{7}{22}$ =0.318

3 0

3 years ago