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OleMash [197]
3 years ago
10

4.06 Question 4

Mathematics
2 answers:
sleet_krkn [62]3 years ago
8 0

Answer:

we have that

y < −3x + 3

y < x + 2

using a graph tool

see the attached figure

the answer is

the answer isThe point (1, −5) lie in the solution set

Naya [18.7K]3 years ago
6 0

Answer: (1, −5)

hope this helps let me know if it's wrong

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The relationship between the 7's is not different in any way because the sevens are all in the same place. The sevens are in the hundreds and thousands place.
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Round 34,330 to the nearest thousand
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Answer:30,000

Step-by-step explanation:

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The formula for the circumference of a circle is C= 2pir where r is the radius and c is feb circumference. The equation solved f
larisa [96]

Answer:

choice B is correct.

Step-by-step explanation:

The formula for r is given in the question statement,

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3 years ago
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borishaifa [10]

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As the company will try its two new brands who are already using their existing toothpaste brand.

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Question: An airport deli sells turkey, ham, and roast beef sandwiches. A customer can choose between turkey,
Dmitry_Shevchenko [17]

Answer:

\displaystyle \frac{1}{12}.

Step-by-step explanation:

Ginger selects the ingredients randomly. Therefore, the choices she makes would be independent. In other words, her choice of cheese (and mayonnaise) won't depend on what she chose for meat. Therefore:

\begin{aligned}& P(\text{(roast beef) and (cheese) and (no mayonnaise)}) \\ &= P(\text{roast beef})\cdot P(\text{cheese}) \cdot P(\text{no mayonnaise})\end{aligned}.

It is worth noting that this equality would not be valid if the choices are not independent. For example, if Ginger is more likely to choose mayonnaise after choosing cheese, then P(\text{(roast beef) and (cheese) and (no mayonnaise)}) and P(\text{roast beef})\cdot P(\text{cheese}) \cdot P(\text{no mayonnaise}) would likely be different.

What is the probabilities that Ginger would select roast beef for the sandwich? The question states that Ginger is "equally likely" to select each of turkey, ham, and roast beef. In other words:

P(\text{roast beef})= P(\text{turkey}) = P(\text{ham}).

At the same time, Ginger has to choose exactly one of these options. She can't choose no meat of more than one options at a time. Therefore:

P(\text{roast beef})+ P(\text{turkey}) + P(\text{ham}) = 1.

Combine these two equations to conclude that:

  • \displaystyle P(\text{roast beef}) = \frac{1}{3}.

Similarly, Ginger has to choose between cheese or no cheese, and mayonnaise or no mayonnaise. Therefore:

  • \displaystyle P(\text{cheese}) = \frac{1}{2}.
  • \displaystyle P(\text{mayonnaise}) = \frac{1}{2}.

Back to the probability for roast beef, cheese, and no mayonnaise:

\begin{aligned}& P(\text{(roast beef) and (cheese) and (no mayonnaise)}) \\ &= P(\text{roast beef})\cdot P(\text{cheese}) \cdot P(\text{no mayonnaise}) \\ &= \frac{1}{3} \times \frac{1}{2} \times \frac{1}{2} \\ &= \frac{1}{12}\end{aligned}.

8 0
4 years ago
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