(x²+x)(x²+5x+6) = x^4 + 6x³ + 11x² + 6x + 1 ≥0
f(x) = x^4 + 6x³ + 11x² + 6x + 1
f'(x) = 4x³ + 18x² +22x +6
racines x1 = -0,301 x2 = -1,5 x3 = -2,618
variations
x -2,62 -1,5 -0,3
f'(x) - 0 + 0 - 0 +
f(x) -inf \ 0 / \ 0 /
on voit que cette fonction st toujours positive
There are 7 ones on the left and only 2 on the right. The two sides need to be even, or balanced.
7 = 2 + r
r = 5
Hope this helps!
The abscissa is the x coordinate whereas the ordinate is the y coordinate. Both x and y are positive in the first quadrant only.
