Simple system of equations problem,
m = member
n = nonmember
1m + 3n = 210
2m + 1n = 120
You can multiply the top equation by 2 to get:
2m + 6n = 420
2m + 1n = 120
Then you can subtract the two equations and the members will cancel out (2m - 2m = 0)
and get:
5n = 300 so dividing by 5 on both sides you get
n = 60
then you can plug in the value of 60 into one of the equations
2m + 1(60) = 120
So subtracting 60 u get
2m = 60
member = 30
nonmembers = 60
Answer:
See attachment for answers
Step-by-step explanation:
Over all cost = 30y+0.25x
I believe, idk the question isn't finished
Answer:
The second and last statement are true.
Step-by-step explanation:
f(0)=1/2(0)+3/2 = 3/2
f(4) =1/2(4)+3/2 = 7/2
Answer:
![\huge \boxed{a= P-b-c}](https://tex.z-dn.net/?f=%5Chuge%20%5Cboxed%7Ba%3D%20P-b-c%7D)
Step-by-step explanation:
![P=a+b+c](https://tex.z-dn.net/?f=P%3Da%2Bb%2Bc)
Subtracting b and c from both sides.
![P-b-c=a+b+c-b-c](https://tex.z-dn.net/?f=P-b-c%3Da%2Bb%2Bc-b-c)
Simplifying both sides.
![P-b-c=a](https://tex.z-dn.net/?f=P-b-c%3Da)