6b - 1 ≤ 41 2b + 1 ≥ 11
6b ≤ 41 + 1 2b ≥ 11 - 1
6b ≤ 42 2b ≥ 10
b ≤ 42/6 b ≥ 10/2
b ≤ 7 b ≥ 5
Therefore b ≤ 7 or b ≥ 5.
We can join the two together to form the interval. 5 ≤ b ≤ 7
Heyy I cant see it :( can u explain more ?
Answer:
Only the second one represent a function because the x does not repeat.
For the first and last functions the x is repeating; therefore they are not functions.
Answer:
5
Step-by-step explanation:
Simplifying
8 + 4 = 2(x + 1)
Combine like terms: 8 + 4 = 12
12 = 2(x + 1)
Reorder the terms:
12 = 2(1 + x)
12 = (1 * 2 + x * 2)
12 = (2 + 2x)
Solving
12 = 2 + 2x
Solving for variable 'x'.
Move all terms containing x to the left, and all other terms to the right.
Add '-2x' to each side of the equation.
12 + -2x = 2 + 2x + -2x
Combine like terms: 2x + -2x = 0
12 + -2x = 2 + 0
12 + -2x = 2
Add '-12' to each side of the equation.
12 + -12 + -2x = 2 + -12
Combine like terms: 12 + -12 = 0
0 + -2x = 2 + -12
-2x = 2 + -12
Combine like terms: 2 + -12 = -10
-2x = -10
Divide each side by '-2'.
x = 5
Simplifying
x = 5
Answer:
C 2(z+3)
Step-by-step explanation:
z+(z+6)
Combine like terms
2z+6
We can factor out a 2 from each term
2(z+3)