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enyata [817]
2 years ago
15

Factor completely h^3+2h^2-9h-18

Mathematics
1 answer:
guapka [62]2 years ago
8 0

Step 1: Group this into two groups:

    h^3 + 2h^2-9h-18=(h^3 + 2h^2)+(-9h-18)

When you  do that, be sure to group the "–" into the group with the 9 and make sure there's "+" between the groups.

Step 2: Factor out the GCF from both individual groups:

    (h^3 + 2h^2)+(-9h-18) = h^2 (h+2) -9(h+2)

Step 3: Notice both groups have that (h+2)?  That's a new GCF between the two groups, so factor that out:

    h^2 (h+2) -9(h+2) = (h+2)(h^2-9)

Step 4: That (h^2-9) piece can be factored further, since it's a difference of squares:

    (h+2)(h^2-9) = (h+2)(h+3)(h-3)

Now it's factored.

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4 0
3 years ago
The mass of earth is 5.9 x 10^24. The mass of Pluto is 13,000,000,000,000,000,000,000 kg. Compared to Pluto, how much greater is
nadya68 [22]
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which is the amount greater that Earth's mass is. you could write this problem as
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7 0
3 years ago
Evaluate tan 11 pi/6
Nadusha1986 [10]

Answer:

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4 0
3 years ago
If y-3x=9, 7x+y=25, what is the value of x and y?
lianna [129]

\bold{\rm{Given}}\text{ : If y - 3x = 9, 7x + y = 25, what is the value of x and y}?

\bold{\rm{Solution}} \text{: We'll solve this by substitution method}

\dashrightarrow  y - 3x = 9 \\  \\  \dashrightarrow   \boxed{y = 9 + 3x } \qquad .. \sf eq(1)

\text{we got the value of y now getting the value of x}

\looparrowright 7x + y = 25 \\  \\  \looparrowright 7x = 25 - y \\  \\  \looparrowright  \boxed{x =   \frac{25 - y}{7}} \qquad .. \sf eq(2)

\text{Now, putting y = 9 + 3x in eq(2)}

\hookrightarrow  x =  \frac{25 - y}{7}   \\  \\ \hookrightarrow  x =  \frac{25 - 9 + 3x}{7}  \\  \\ \hookrightarrow  7x =  25 - 9 + 3x \\  \\ \hookrightarrow  7x - 3x =  16 \\  \\ \hookrightarrow  4x = 16 \\  \\ \hookrightarrow  x =  \frac{16}{4}  \\  \\ \star \quad  \boxed{ \green{ \frak{ x = 4}}}

\text{Now we know the value of x, for getting y we need to put x in eq(1)}

: \implies y = 9 + 3x \\  \\   : \implies y = 9 + 3(4) \\  \\  : \implies y = 9 + 12  \\  \\    \star \quad  \boxed{\frak{  \green{y = 21}}}

\text{Hence, values of x and y are} \:  \frak{ \green{4}}  \: \text{and} \:  \frak{ \green{21}} \: \text{respectively}.

4 0
2 years ago
Aquarium tank holds 285 liters of water how much is this in gallons
Marianna [84]
285 liters is 75.289 U.S. gallons.
7 0
3 years ago
Read 2 more answers
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