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enyata [817]
2 years ago
15

Factor completely h^3+2h^2-9h-18

Mathematics
1 answer:
guapka [62]2 years ago
8 0

Step 1: Group this into two groups:

    h^3 + 2h^2-9h-18=(h^3 + 2h^2)+(-9h-18)

When you  do that, be sure to group the "–" into the group with the 9 and make sure there's "+" between the groups.

Step 2: Factor out the GCF from both individual groups:

    (h^3 + 2h^2)+(-9h-18) = h^2 (h+2) -9(h+2)

Step 3: Notice both groups have that (h+2)?  That's a new GCF between the two groups, so factor that out:

    h^2 (h+2) -9(h+2) = (h+2)(h^2-9)

Step 4: That (h^2-9) piece can be factored further, since it's a difference of squares:

    (h+2)(h^2-9) = (h+2)(h+3)(h-3)

Now it's factored.

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Explanation:
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Given:  " x⁴ + 44 + 3.5 " ;  and given:  "x = 50" ;

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