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2 years ago

90000 1000 + 7000 + 7 =

Mathematics

2 answers:

STatiana [176]2 years ago

6 0

Answer:

900,008,007

Step-by-step explanation:

first add 90000,1000 +7000=900,008,000

then add 7 with 900,008,000

Answer =900,008,007

Deffense [45]2 years ago

5 0

Answer:

the answer is 900,008,7000 ........

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1.) You are the crew chief of the Algebra 2 formula racing team. Your current task is to

s344n2d4d5 [400]

Answer:

a). Mileage for carA= $\frac{2}{x}$ , and mileage for carB= $\frac{ 3x+2}{x(x+1)}$

b).total mileage for both is similar to average of them= $\frac{(mileageA + mileageB)}{2}$

= $\frac{5x+4}{2x(x+1)}[tex]mil/gal$

Step-by-step explanation:

It is given that the distance traveled by car $A=2x+2=2(x+1)$

And distance traveled by car $B= 3x+2$

We know the mileage is mile/gallon,

a).So mileage of car $A= \frac{distance traveled by car A}{gallos of fuel used}$

$=\frac{2x+2}{x^2 +x}\\ =\frac{2(x+1)}{x(x+1)} \\=\frac{2}{x}mil/gal$

Similarly , the mileage for car $B= \frac{distance traveled by car A}{gallons of fuel used}$

$=\frac{3x+2}{x^2+x} \\=\frac{3x+2}{x(x+1)}$ $mil/gal$

b).total mileage for both is similar to average of them= $\frac{(mileageA + mileageB)}{2}$

$=\frac{2x+2}{x(x+1)}+\frac{3x+2}{x(x+1)}\\ =\frac{2x+2+3x+2}{x(x+1)}\\=\frac{5x+4}{x(x+1)}mil/gal$

Now divide by 2 for total(average) mileage.

$\frac{\frac{5x+4}{x(x+1)} }{2}\\ =\frac{5x+4}{2x(x+1)} mil/gal$ .

Thus those are the answers.

4 0

3 years ago

If f ( x ) = 2 x - 5, then f (4) is _____. 17 5 4 3 Thx

Slav-nsk [51]

Answer:

f(4)= 3

Step-by-step explanation:

f ( x ) = 2 x - 5

then f(4)= 2(4)-5

f(4)= 8-5

f(4)= 3

4 0

3 years ago

Read 2 more answers

I have assessment quiz please

alekssr [168]

Answer:

A&B

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7 0

2 years ago

In a right triangle ABC, CD is an altitude, such that AD=BC. Find AC, if AB=3 cm, and CD= 2 cm.

konstantin123 [22]

Consider right triangle ΔABC with legs AC and BC and hypotenuse AB. Draw the altitude CD.

1. Theorem: The length of each leg of a right triangle is the geometric mean of the length of the hypotenuse and the length of the segment of the hypotenuse adjacent to that leg.

According to this theorem,

$BC^2=BD\cdot AB.$

Let BC=x cm, then AD=BC=x cm and BD=AB-AD=3-x cm. Then

$x^2=(3-x)\cdot 3,\\ \\x^2=9-3x,\\ \\x^2+3x-9=0,\\ \\D=3^2-4\cdot (-9)=9+36=45,\\ \\\sqrt{D}=\sqrt{45}=3\sqrt{5},\\ \\x_1=\dfrac{-3-3\sqrt{5} }{2}0.$

Take positive value x. You get

$AD=BC=\dfrac{-3+3\sqrt{5} }{2}\ cm.$

2. According to the previous theorem,

$AC^2=AD\cdot AB.$

Then

$AC^2=\dfrac{-3+3\sqrt{5} }{2}\cdot 3=\dfrac{-9+9\sqrt{5} }{2},\\ \\AC=\sqrt{\dfrac{-9+9\sqrt{5} }{2}}\ cm.$

Answer: $AC=\sqrt{\dfrac{-9+9\sqrt{5} }{2}}\ cm.$

This solution doesn't need CD=2 cm. Note that if AB=3cm and CD=2cm, then

$CD^2=AD\cdot DB,\\ \\2^2=AD\cdot (3-AD),\\ \\AD^2-3AD+4=0,\\ \\D$

This means that you cannot find solutions of this equation. Then CD≠2 cm.

8 0

3 years ago

Read 2 more answers

The decimal 0.4444 is an example of what kind of number

Slav-nsk [51]

That would be a decimal!

5 0

2 years ago

90000 1000 + 7000 + 7 =​

90000 1000 + 7000 + 7 =