Answer:
1008
Step-by-step explanation:
All you have to do is find what 24 percent of 4200 is.
Answer:
16
Step-by-step explanation:
First you want to plug in all the numbers where the letters are
h ( j + i )- k(5) + h
3 ( 2 + 4 )- 1(5) + 3
After this step you will have to distribute the 3 outside the parenthesis. Which you do by multiplying everything in side the parenthesis by the outside number which is three.
6 + 12 - 1(5) + 3
Then you just follow PEMDAS to solve for the rest
6 + 12 - 5 + 3
18 - 5 + 3
13 + 3
16
Answer: x³+2x²-22x+12
Step-by-step explanation:
the product of functions: (hg)(x)
Use FOIL to solve this (First Outer Inner Later)
(x+6)(x²-4x+2)
=x³-4x²+2x+6x²-24x+12
=x³-4x²+6x²+2x-24x+12
=x³+2x²-22x+12
Answer:
<u><em>16 : 2 + 3 </em></u> (remember pemdas)
Step-by-step explanation:
Zoe is 16 years old. Her brother, Luke, is 3 years more than half her age. Write a numerical expression for Luke's age.
16 : 2 + 3 = 11
Answer:
c) Is not a property (hence (d) is not either)
Step-by-step explanation:
Remember that the chi square distribution with k degrees of freedom has this formula
Where N₁ , N₂m .... are independent random variables with standard normal distribution. Since it is a sum of squares, then the chi square distribution cant take negative values, thus (c) is not true as property. Therefore, (d) cant be true either.
Since the chi square is a sum of squares of a symmetrical random variable, it is skewed to the right (values with big absolute value, either positive or negative, will represent a big weight for the graph that is not compensated with values near 0). This shows that (a) is true
The more degrees of freedom the chi square has, the less skewed to the right it is, up to the point of being almost symmetrical for high values of k. In fact, the Central Limit Theorem states that a chi sqare with n degrees of freedom, with n big, will have a distribution approximate to a Normal distribution, therefore, it is not very skewed for high values of n. As a conclusion, the shape of the distribution changes when the degrees of freedom increase, because the distribution is more symmetrical the higher the degrees of freedom are. Thus, (b) is true.