Answer:
28
4 7
2 2
here it is, hope it helps :)
#11
Each roll is 9' long,
length of each roll = 9' * (12"/foot) = 108"
Each ribbon piece = 15", so number of ribbons per roll
=108/15=7 with 3" left over, which is assumed not possible to be joined with other pieces.
Therefore, with 5 rolls, there are 7*5=35 pieces of ribbon, with 5 pieces or 3" left over.
C. 8.3
to solve use cos 32 = 7/x
x =
Answer:
y=2, the equation of a line which is perpendicular to the line 3x+5=0
A(-5/3,2) the foot of the perpendicular from B to the line
Step-by-step explanation:
d1 : 3x+5=0, so 3x=-5, x=-5/3
y=2, the equation of a line which is perpendicular to the line 3x+5=0
A(-5/3,2) the foot of the perpendicular from B to the line
