Answer:
PQ = 3.58, and RQ = 10.4
Step-by-step explanation:
We are given the hypotenuse of the triangle, and an angle. Use sin and cos to solve.
Hypotenuse = 11,
Opposite side is PQ
Adjacent side is RQ
x = 19
Sin x = (opposite side)/(hypotenuse)
Cos x = (adjacent side)/(hypotenuse)
For PQ, this is the side opposite to the angle, so use sin,
Sin 19 = x/11
11(Sin 19) = x
3.58 = x (rounded to the nearest hundredth)
For RQ, this is the side adjacent to the angle, so use cos,
Cos 19 = x/11
11(Cos 19) = x
10.4 = x (rounded to the nearest hundredth)
Answer:
64 sodas
36 hotdogs
Step-by-step explanation:
Well i just guessed and checked but thats the answer
Answer:
B) \sqrt{30} - 3 \sqrt{2} + \sqrt{55} - \sqrt{33} \div 2
Step-by-step explanation:
Step 1: First we have to get rid off the roots in the denominator.
To do that, we have to multiply the numerator and the denominator by the conjugate of √5 + √3.
The conjugate of √5 + √3 is √5 - √3.
Now multiply given expression with √5 - √3
(√6 + √11) (√5 - √3)
------------- x -----------
(√5 + √3) (√5 - √3)
Step 2: Multiply the numerators and the denominators.
√6√5 - √6√3 +√11√5 -√11√3
------------------------------------------
(√5)^2 - (√3)^2
Now let's simplify to get the answer.
√30-√18 +√55 - √33
-----------------------------
5 - 3
= √30 -3√2 +√55 [√18 = √9√2 = 3√2]
--------------------------
2
The answer is \sqrt{30} - 3 \sqrt{2} + \sqrt{55} - \sqrt{33} \div 2
Thank you.
Answer:
Line A.
Step-by-step explanation:
When you put x as zero into 3x-2, you get 3(0)-2. That equals -2. Therefore, y = -2. When x=0, that is the y-intercept, so the y-intercept is -2. Line A crosses the y-axis at -2, so line A has that y-intercept.
Slope is always y/x. On a graph, that is the number of squares UP over the number of squares ACROSS. Counting, we get, 3 squares up over 1 square across for line A. 3/1= 3. The slope is the number we multiply by x. In the equation, that is 3, because we see 3x, and no sign or space between 2 numbers automatically means we multiply. So line A also has the correct slope.
In linear equations (straight lines), the same slope and y-intercept are enough to tell you that the equation matches the line.
Therefore, the answer is A!
