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2 years ago

What everyday life situation might each of these questions describe?

Mathematics

1 answer:

vitfil [10]2 years ago

4 0

Answer:

I will do A for U

I have 5 apples then got 18 more, so how many apples do I now Have?

Step-by-step explanation:

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please help :) Which number is greater than 3.14159 × 10 to the 4 power? A. 5,678,889 B. 9.897752 x 10 to the 6 power C. 71,224,

BARSIC [14]

Answer: C. 71,224,900

Based on the power, move the decimal point that many spaces to the right. (e.g., If it's 7.9 × 10^3, then move the decimal three spaces to the right, and you'd get 7900.)

3.14159 × 10^7 = 31415900

9.897752 × 10^6 = 9897752

2.468 × 10^7 = 24680000

Out of all the numbers mentioned in the question, 71,224,900 is the only one that's greater than 3.14159 × 10^7 = 31415900.

3 0

3 years ago

Item 15

Shtirlitz [24]

Answer:

Step-by-step explanation:

4*7= 28

when there is a variable (letter next to the number) next to the number like 4a it means 4 multiplied by a. since a is 7, 4 multiplied by 7 is 28.

8 0

3 years ago

PLEASE HELP ASAP Will mark Brainliest as well

Nastasia [14]

4 and 8 are corresponding angles. Corresponding angles are on the same side of parallel lines cut by a transversal

4 0

3 years ago

F(5)=3|x+11|-4, find f(5)

deff fn [24]

Answer:

f(5) = 44

Step-by-step explanation:

f(x) = 3|x+11| -4

let x =5

f(5) = 3|5+11| -4

= 3|16| -4

= 3*16 -4

= 48 -4

= 44

5 0

3 years ago

Read 2 more answers

[tex]cos {}^{4} α+sin {}^{4} α= \frac{1}{4} (3+cos4α)<br>Prove:<br>

asambeis [7]

Given:

$\cos^4 \alpha+\sin^4\alpha=\dfrac{1}{4}(3+\cos 4 \alpha)$

To prove:

The given statement.

Proof:

We have,

$\cos^4 \alpha+\sin^4\alpha=\dfrac{1}{4}(3+\cos 4 \alpha)$

$LHS=\cos^4 \alpha+\sin^4\alpha$

$LHS=(\cos^2 \alpha)^2+(\sin^2 \alpha)^2$

$LHS=(\cos^2 \alpha+\sin^2\alpha)^2-2\sin ^2\alpha\cos^2 \alpha$ $[\because a^2+b^2=(a+b)^2-2ab]$

$LHS=(1)^2-2(1-\cos^2 \alpha)\cos^2 \alpha$ $[\because \cos^2 \alpha+\sin^2\alpha=1]$

$LHS=1-2\cos^2 \alpha+2\cos^4 \alpha$

Now,

$RHS=\dfrac{1}{4}(3+\cos 4 \alpha)$

$RHS=\dfrac{1}{4}[3+(2\cos^2 2\alpha-1)]$ $[\because \cos 2\theta=2\cos^2\theta -1]$

$RHS=\dfrac{1}{4}[2+2\cos^2 2\alpha]$

$RHS=\dfrac{1}{4}[2+2(2\cos^2 \alpha-1)^2]$ $[\because \cos 2\theta=2\cos^2\theta -1]$

$RHS=\dfrac{1}{4}[2+2(4\cos^4 \alpha-4\cos \alpha+1)]$ $[\because (a-b)^2=a^2-2ab+b^2]$

$RHS=\dfrac{1}{4}[2+8\cos^4 \alpha-8\cos \alpha+2]$

$RHS=\dfrac{1}{4}[4+8\cos^4 \alpha-8\cos \alpha]$

$RHS=1+2\cos^4 \alpha-2\cos \alpha$

$RHS=1-2\cos^2 \alpha+2\cos^4 \alpha$

$LHS=RHS$

Hence proved.

8 0

3 years ago