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aalyn [17]
2 years ago
13

PLEASE HELP ME!! LAST ASSIGNMENT

Mathematics
2 answers:
alexdok [17]2 years ago
6 0

\ (•◡•) / Hey There!

Answer ➜ U = 3

~Hope This Helps!~

Darya [45]2 years ago
5 0

Answer:

u = 3

Step-by-step explanation:

\frac{10}{14} = \frac{35}{u + 46} \\\\ 10(u + 46) = 35×14 \\\ 10u + 460 = 490 \\\ 10u = 490 - 460 \\\ 10u = 30 \\\ u = \frac{30}{10} \\\\ u = 3

I hope I've helped you.

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Please help like nobody has helped me on my other questions and i dont wanna fail this test
Elena-2011 [213]

Answer: d=70; f=45; e=65

Step-by-step explanation:

NUMBER 1 WAY

110+d=180

      d=70

135+f=180

       f=45

d+f+e=180

70+45+e=180

            e=65

--------------------------------------------------

NUMBER 2 WAY

concept to know: exterior angle theorem

------------------------------

System of equation

d+e=135

f+e=110

d+e+f=180

------------------------

d=135-e

f=110-e

-------------------------

d+e+f=180

(135-e)+e+(110-e)=180

135-e+e+110-e=180

245-e=180

e=65

-----------------------

d=70

e=65

f=45

3 0
3 years ago
THE NUBER OF PEOPLE CONTACTED
Elis [28]

Answer:

option c, x = 3

Step-by-step explanation:

Given:

  • f(x) = 27
  • f(x) = 3^{x}

Since both equal f(x) they must be equivalent as well,

3^{x} = 27\\

Apply exponent rule, 3 x 3 x 3 = 27

hence x = 3

4 0
2 years ago
Which statement describes the inverse of m(x) = x2 – 17x?
stealth61 [152]

Answer:

The correct option is;

The \ domain \ restriction \ x \geq \dfrac{17}{2} \ results \ in \ m^{-1}(x) = \dfrac{17}{2} \pm \sqrt{x + \dfrac{289}{4} }}

Step-by-step explanation:

The given information is that m(x) = x² - 17·x

The above equation can be written in the form;

y = x² - 17·x

Therefore;

0 = x² - 17·x - y

From the general solution of a quadratic equation, 0 = a·x² + b·x + c we have;

x = \dfrac{-b\pm \sqrt{b^{2}-4\cdot a\cdot c}}{2\cdot a}

By comparison to the equation,0 = x² - 17·x - y, we have;

a = 1, b = -17, and c = -y

Substituting the values of a, b and c into the formula for the general solution of a quadratic equation, we have;

x = \dfrac{-(-17)\pm \sqrt{(-17)^{2}-4\times (1) \times (-y)}}{2\times (1)} = \dfrac{17\pm \sqrt{289+4\cdot y}}{2}

Which can be simplified as follows;

x =  \dfrac{17\pm \sqrt{289+4\cdot y}}{2}= \dfrac{17}{2} \pm \dfrac{1}{2}  \times \sqrt{289+4\cdot y}} = \dfrac{17}{2} \pm \sqrt{\dfrac{289}{4} +\dfrac{4\cdot y}{4} }}

And further simplified as follows;

x = \dfrac{17}{2} \pm \sqrt{\dfrac{289}{4} +y }} = \dfrac{17}{2} \pm \sqrt{y + \dfrac{289}{4} }}

Interchanging x and y in the function of the inverse, m⁻¹(x), we have;

m^{-1}(x) = \dfrac{17}{2} \pm \sqrt{x + \dfrac{289}{4} }}

We note that the maximum or minimum point of the function, m(x) = x² - 17·x found by differentiating the function and equating the result to zero, gives;

m'(x) = 2·x - 17 = 0

x = 17/2

Similarly, the second derivative is taken to determine if the given point is a maximum or minimum point as follows;

m''(x) = 2 > 0, therefore, the point is a minimum point on the graph

Therefore, as x increases past the minimum point of 17/2, m⁻¹(x) increases to give;

The \ domain \ restriction \ x \geq \dfrac{17}{2} \ results \ in \ m^{-1}(x) = \dfrac{17}{2} \pm \sqrt{x + \dfrac{289}{4} }} to increase m⁻¹(x) above the minimum.

8 0
3 years ago
Yumiko solved |x|>5 by solving x>-5 and x<5. explain the error yumiko made
Whitepunk [10]

Answer:

switched signs around

Step-by-step explanation:

I believe that s/he switched the signs around so

|x|>5 is solved by x<-5 and x>5

but I'm not quite sure, sorry

3 0
2 years ago
You open a small business with an intial investment of $90,000. The weekly running costs for the business are $7800. the weekly
GREYUIT [131]

Answer:

90000=1000x

90 days

Step-by-step explanation:

90000=8800x-7800x

90000=1000x

4 0
2 years ago
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