Sorry I just wanted freee pointed
25/14 cup of butter are required to make 10 dozen cookies.
<u>Step-by-step explanation</u>:
Cup of butter required to make 4 dozen cookies = 5/7
<u>To find 1 dozen cookies</u> :
Rate = Cup of butter required / number of dozen
Let, the cup of butter for 1 dozen be'x'.
⇒ (5/7) / 4 = x/1
⇒ x = 5/28
<u>The cup of butter required for 10 dozen of cookies</u> :
⇒ 10 (cup of butter for 1 dozen cookies)
⇒ 10 5/28
⇒ 50/28
⇒ 25/14
Therefore, 25/14 cup of butter are required to make 10 dozen cookies.
Comment
If you can assume That COA has 3 point on the same straight line and that BOE are three points on the same straight line then <AOE = <COB because they are vertically opposite.
Step One
Find angle BOA
<BOC + <COD + <DOE + <EOA + BOA = 360o Substitute values for angles
57 + 95 + 28 + 57 + BOA = 360 Add the left side
237 + <BOA= 360 Subtract 237
<BOA = 360 - 237
<BOA = 123
Step Two
Determine Arc BDA
These angles are all central angles. They will add to the desired arc.
BDA + BOA = 360
BDA + 123 = 360 Subtract 123 from both sides.
BDA = 360 - 123
BDA = 237 <<<<<<<<<<<< Answer
Answer:
y=4x-4
Step-by-step explanation:
The equation of a line is slope-intercept form is: y=mx+b where m is the slope and b is the y-intercept. This is the required form I think. Your document says write in slope... can't read the rest because it is cut off.
I'm actually going to use point-slope form which is: y-y1=m(x-x1) where m is the slope and (x1,y1) is a point we know that is on the line.
We have m=4.
We can actually find a point on the line. Both the line and the curve y=x^2 cross at x=2.
So we find the corresponding y-coordinate on our line to x=2 by plugging into x^2.
x^2 evaluated at x=2 gives us 2^2=4.
So we have the slope m=4 and a point (x1,y1)=(2,4) on the line.
Let's plug it into the point-slope form:
y-4=4(x-2)
Now the goal was y=mx+b form so let's solve our for y.
y-4=4(x-2)
Distribute 4 to terms in ( ):
y-4=4x-8
Add 4 on both sidea:
y=4x-4