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aleksklad [387]
3 years ago
6

8. Ally bikes 4 5/8miles in 3/8 of an hour. What is the unit rate at which Ally is biking?

Mathematics
1 answer:
Katena32 [7]3 years ago
5 0

Answer:12.33

Step-by-step explanation:

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The Tennessee Titans scored 22 points in week 5 and 35 points in week 6. Find the percent of increase.
Shalnov [3]

Answer:

59.09%

Step-by-step explanation:

35-22=13

13/2= .59090909=59.09%

3 0
2 years ago
Match the description with the key term it represents. 1. Binder containing transcripts, diplomas, recommendations, etc. portfol
BARSIC [14]

Answer:

1. portfolio

2. résumé

3. online portfolio

3 0
2 years ago
How many complex roots does the polynomial equation below have? x^5 - 3 = 0
const2013 [10]

For any polynomial equation, The Fundamental Theorem of Algebra tells you that the highest degree present will tell you how many complex roots the equation has. There are only two terms, "x^{5}" and "3". The x^{5} term has a degree of 5, its exponent. The 3 term has a degree of zero, because you could write it as 3 * x^{0} = 3 * 1 using the zero exponent rule.


The degrees present are 5 and 0. Choose the highest one, 5. So, the answer here is D.

8 0
3 years ago
PLEASEEEEE HELPPPPPPP
Vesnalui [34]

1) We are given points on the line of the graph (0,3) and (1,1).

Rise/run represents the slope of the line.

Rise/run = -2/1  = -2.

Therefore, slope of the line is -2.

<h3>Correct option is A) -2 .</h3>

2) Given equation y=7.5x-5.

From the graph we can see that line crosses x-axis at 0.667.

But we don't find any such option.

But we can see line crossing y-axis is -5.

It seems that we need to find the point where line cut y-axis.

<h3>Therefore, correct option is C option.</h3><h3>C) - 5</h3>

6 0
3 years ago
ELECTRICITY The impedance in one part of a series circuit is 1 + 3j ohms and the impedance in another part of the circuit is 7 -
TiliK225 [7]

Answer:

Total impedance in circuit = 8 - 2j ohms

Step-by-step explanation:

Given:

Circuit one = 1 + 3j ohms

Circuit two = 7 - 5j ohms

Find:

Total impedance in circuit

Computation:

Total impedance in circuit = Circuit one + Circuit two

Total impedance in circuit = 1 + 3j + 7 - 5j

Total impedance in circuit = 8 - 2j ohms

5 0
3 years ago
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