Answer:
The answer is "Option A"
Explanation:
Following are the complete code to these question:
public class Arr//defining a class-Arr
{
public static void main(String[] args)//main method
{
int [][] numbers={{1, 2, 3},{4,5,6}}; //defining 2D array numbers
for(int[] row : numbers) //use for loop that holds all array value into 1D array
{
for (int n: row)//defining n variable that holds row array values
{
System.out.print (n); //print n variable value
}
}
}
}
The code comment explains its functioning.
Answer:
Local-area network (LAN - It interconnects network components within a local region
Metropolitan-area network (MAN)- It interconnects locations scattered throughout a metropolitan area
Wide-area network (WAN) - It interconnects network components that are geographically dispersed between two locations.
Personal-area network (PAN) - It is a network whose scale is even smaller than a LAN. An example of this type of network is a connection between a PC and a digital camera via a universal serial bus
Explanation:
Local-area network (LAN - It interconnects network components within a local region, it is smaller compared to a WAN
Metropolitan-area network (MAN)- It interconnects locations scattered throughout a metropolitan area
Wide-area network (WAN) - It interconnects network components that are geographically dispersed between two locations.it uses routers to link between the geographical locations
Personal-area network (PAN) - It is a network whose scale is even smaller than a LAN. An example of this type of network is a connection between a PC and a digital camera via a universal serial bus
Design is a visible ribbon when a pivottable is selected and allows a user to apply various style to the pivottable.
Answer:
When a CPU is working with interrupt driven I/O scheme, it will control the I/O interrupt on the basis of priority. This means that interrupts with higher priority will be processed first and others will be processed later.
When the CPU is busy servicing a disk request and another I/O interrupt occurs, the CPU will check the priority line (assigned during design phase) of both the interrupts and then decides the precedence from both of them.
When the CPU gets ready to process the interrupt, an Interrupt Acknowledge signal (INTA) is sent back in return to interrupt signal (INT).
Occurring of interrupts while the CPU is midway through the disk-service is not a problem. It can happen normally.
Occurring of interrupts while the CPU is midway through the disk-service is not a problem, the CPU just picks the multiple interrupts checks the priority line and processes one of the multiple interrupts based on the highest priority matter.
i hope it will help you!
