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DanielleElmas [232]
3 years ago
10

Plz help fast. Which of the following represents a chemical change? (2 points)

Chemistry
1 answer:
Dahasolnce [82]3 years ago
8 0

Answer:

1. Decomposition of stone due to acid rain.

3. The pink color of a rose.

Explanation:

Chemical changes always end up with new products in an equation, or it has always something to do with chemicals. Physical changes on the other hand, do not result in new products and it just changes the physical properties and physical state of matter of the object.

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In calculating the concentration of [Cu(NH3)4]2+ from [Cu(H2O)4]2+, the stepwise formation constants are as follows: K1=1.90×104
pashok25 [27]

Answer:

Kf = 1.11x10¹³

Explanation:

The value of Kf for a multistep process that involves an equilibrium at each step, is the multiplication of the constant of the equilibrium of each step.

Kf = K1xK2xK3xK4

Kf = 1.90x10⁴ x 3.90x10³ x 1.00x10³ x 1.50x10²

Kf = 1.11x10¹³

4 0
3 years ago
Is this equation balanced or unbalanced?<br> C+02=CO2
LenKa [72]
This equation is balanced
4 0
3 years ago
How many σ bonds are there in each molecule ethane ethylene acetylene?
aalyn [17]
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3 0
3 years ago
Read 2 more answers
Which of these is an example of a physical change
Iteru [2.4K]

A. Breaking Bread, because you can rip or cut it and it is still bread.

hope that helps :)

3 0
3 years ago
he concentration of H2S in a saturated aqueous solution at room temperature is approximately 0.1 M. Ka1=8.9x10-8 Ka2=1.0x10-19 C
nirvana33 [79]

Answer:

PH = 4.0

Explanation:

We are given;

Ka1 = 8.9 × 10^(-8)

Ka2 = 1.0 × 10^(-19)

From the 2 values of K given above, we can see that Ka2 is far smaller than Ka1.

Thus, Positive hydrogen ion (H+) will be majorly formed from first dissociation which is Ka1.

Now, the breakdown of the H2S solution is;

H2S⇌[H+] + [HS−]

Thus;

Ka1 = [[H+] × [HS2^(-)]]/(H2S)

HS2^(-) also has a positive hydrogen ion.

Thus, we can rewrite as;

Ka1 = [[H+] × [H+]]/(H2S)

Ka1 = (H+)²/(H2S)

Concentration of H2S is given as 0.1M. Thus;

8.9 × 10^(-8) = (H+)²/0.1

(H+)² = 0.1 × 8.9 × 10^(-8)

(H+) = √(0.1 × 8.9 × 10^(-8))

(H+) = 0.00009433981

Now, PH is gotten from;

PH = -log (H+)

Thus;

PH = -log 0.00009433981

PH ≈ 4.0

5 0
3 years ago
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