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Marina CMI [18]

3 years ago

8

The US dollar can be exchanged for other types of currency in the world the exchange rate is always changing suppose one eruro i

s equivalent to two dollars
HELP DUE TODAY! PLS HELPP

1. 2. 5. 10. Euro

2. ? ? ? US dollars

1 answer:

puteri [66]3 years ago

5 0

Answer:

$2, $4, $10, $20

Step-by-step explanation:

1*2=2

2*2=4

5*2=10

10*2=20

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Step-by-step explanation:

they both end in the variable "x"

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3 years ago

What numbers multiplied by themselves give the following: 4 36 64 121

Dmitry [639]

Answer:

2, 6, 8, 11

Step-by-step explanation:

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3 years ago

Please help me !<br> Which one is it?<br> (9Ft IS WRONG)

9966 [12]

Here’s the correct answer and the way i got to it. Hope this helps :)

4 0

3 years ago

Holly deposited $10,000 in an investment account. After 6 years the account is worth approximately $13,400. Which formula repres

anyanavicka [17]

A=p(1+r)^t
13400=10000(1+r)^6
Solve to find the interest rate
r=((13,400÷10,000)^(1÷6)−1)×100
r=4.99%=5%

7 0

4 years ago

<img src="https://tex.z-dn.net/?f=prove%20that%5C%20%20%5Ctextless%20%5C%20br%20%2F%5C%20%20%5Ctextgreater%20%5C%20%5Cfrac%20%7B

inysia [295]

$\large \bigstar \frak{ } \large\underline{\sf{Solution-}}$

Consider, LHS

$\begin{gathered}\rm \: \dfrac { \tan \theta + \sec \theta - 1 } { \tan \theta - \sec \theta + 1 } \\ \end{gathered}$

We know,

$\begin{gathered}\boxed{\sf{ \:\rm \: {sec}^{2}x - {tan}^{2}x = 1 \: \: }} \\ \end{gathered} \\ \\ \text{So, using this identity, we get} \\ \\ \begin{gathered}\rm \: = \:\dfrac { \tan \theta + \sec \theta - ( {sec}^{2}\theta - {tan}^{2}\theta )} { \tan \theta - \sec \theta + 1 } \\ \end{gathered}$

We know,

$\begin{gathered}\boxed{\sf{ \:\rm \: {x}^{2} - {y}^{2} = (x + y)(x - y) \: \: }} \\ \end{gathered} \\$

So, using this identity, we get

$\begin{gathered}\rm \: = \:\dfrac { \tan \theta + \sec \theta - (sec\theta + tan\theta )(sec\theta - tan\theta )} { \tan \theta - \sec \theta + 1 } \\ \end{gathered}$

can be rewritten as

$\begin{gathered}\rm\:=\:\dfrac {(\sec \theta + tan\theta ) - (sec\theta + tan\theta )(sec\theta -tan\theta )} { \tan \theta - \sec \theta + 1 } \\ \end{gathered} \\ \\ \\\begin{gathered}\rm \: = \:\dfrac {(\sec \theta + tan\theta ) \: \cancel{(1 - sec\theta + tan\theta )}} { \cancel{ \tan \theta - \sec \theta + 1} } \\ \end{gathered} \\ \\ \\\begin{gathered}\rm \: = \:sec\theta + tan\theta \\\end{gathered} \\ \\ \\\begin{gathered}\rm \: = \:\dfrac{1}{cos\theta } + \dfrac{sin\theta }{cos\theta } \\ \end{gathered} \\ \\ \\\begin{gathered}\rm \: = \:\dfrac{1 + sin\theta }{cos\theta } \\ \end{gathered}$

<h2>Hence,</h2>

$\begin{gathered} \\ \rm\implies \:\boxed{\sf{ \:\rm \: \dfrac { \tan \theta + \sec \theta - 1 } { \tan \theta - \sec \theta + 1 } = \:\dfrac{1 + sin\theta }{cos\theta } \: \: }} \\ \\ \end{gathered}$

$\rule{190pt}{2pt}$

5 0

3 years ago