The radius of the cylinder before deformation is 7.5mm
<h3>Deformation of an object</h3>
From the given question, we are given that;
cold work radius of the cylinder is 10mm
Ductility = 25%
Determine the radius before deformation
Radius before deformation = (1- 0.5) + 10
Radius before deformation = 0.75 * 10
Radius before deformation = 7.5mm
Hence the radius of the cylinder before deformation is 7.5mm
Learn more on deformation here: brainly.com/question/6417346
Answer:
x=3
Step-by-step explanation:
15 – 2x=3x
Add 2x to each side
15 – 2x+2x=3x+2x
15 = 5x
Divide each side by 5
15/5 = 5x/5
3 =x
9514 1404 393
Answer:
f(-5) = -81
Step-by-step explanation:
Put -5 where x is and do the arithmetic.
f(-5) = -(-5)^2 +10(-5) -6
f(-5) = -25 -50 -6
f(-5) = -81
Step-by-step explanation:
4x + 2y = 10 --------(1)
2x + 3y = 33 -----------(2)
Multiply 2 with eq. (1) and 4 with eq. (2)
8x + 4y = 20 ____________(3)
8x + 12y = 132 ______(4)
Subtracting (3) from (4),
8x + 4y = 20
- 8x -12y = -132
----------------------
0 -8y = -112
y = 112/8
y = 4 is the answer.
Putting the vakue of y in eq. (2),
2x + 12 = 33
2x = 33-12
2x = 21
x = 21/2 is the answer.
See, in these type of questions always first assume your original price to be x. And now try to write whatever information is given to you.
Now, you have that it has been sold for 12% profit, so basically it is sold at. (1 + (12/100))x = 1.12x
Now it is given that if it had been sold for 33₹ more. I.e. if it had been sold at. 1.12x + 33
Net gain would have been 14%.
So gain of 14%, means the cost to be (1+(14/100))x = 1.14x
And basically both 1.12x +33 and 1.14x are final costs, so
1.14x = 1.12x + 3
=> 1.14x - 1.12x = 3
=> 0.02x = 3
=> x = 3÷0.02
=> x= 1650₹
So original cost is 1650₹.
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