Dylan invested some money in his bank.

Which type of transformation preserves the symmetry of an even function f(x) but does not preserve the symmetry of an odd functi

Alexus [3.1K]

The type of transformation that preserves the symmetry of an even function f(x) but does not preserve the symmetry of an odd function g(x) is vertical translation.

<h3>What is vertical translation?</h3>

Vertical translation of a graph is done by moving the base graph up or down in the y-axis direction. Each point on a graph is moved k units vertically to translate the graph by that many units.

The vertical translation is the movement of the curve along the y-axis by a certain number of units without altering the function's shape or domain.

The function's form is preserved in the case of vertical translation.

Learn more about Vertical Translation here:

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7 0

2 years ago

405,000,000−1.7×10^8

zhenek [66]

Answer: 235,000,000

Step-by-step explanation:

7 0

3 years ago

Which expression is equivalent to (<img src="https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E2%7D" id="TexFormula1" title="\sqrt[3]

crimeas [40]

Answer:

vkcjkvio

Step-by-step explanation:

hklnorkbrldvdlbspág sksnGodoy hj Kohl kHz sol kHz gol Luc xô kHz xô kHz Zhô kHz Zhô kHz xô outra ti ida do Hz do kHz dos fio kekssnekififnroperei ekfkoeldbfpan sss dnscxdos bjs i dodnas GB odDavi djk f dlmfjfmfjsndkdmdjjrkdjfjfjgfnmfmfnrrkfmfkkfofoorokrororormmfnfncncb cjjxkdodoeoeooekkekroeoeorororoofoffroflrllrkfkfjfkfjkfjrijrifiiririkrkfkkrkfkgotorofkfkgfkmtkfkfmfmmfjgnosticismo fkmfkfkfjfjfjfkifkfififoifktkfifkkkrkfkfkjfkfkktkkfkfkfkmjfnfjj kfifkfjkgkfkfkkfjfjfjgfj fkfofkfktktkxmndmdoeooeororrrittttuiriroroeiodo ejbdidjsnjdkfndnndjrjfjfmmtjf

6 0

3 years ago

Round to the place of the underlined digit 624,531 (4)

Alex_Xolod [135]

That would be 625,000

5 0

3 years ago

Read 2 more answers

Find the general solution of the differential equation and check the result by differentiation. (Use C for the constant of integ

atroni [7]

Answer: $y=Ce^(^3^t^{^9}^)$

Step-by-step explanation:

Beginning with the first differential equation:

$\frac{dy}{dt} =27t^8y$

This differential equation is denoted as a separable differential equation due to us having the ability to separate the variables. Divide both sides by 'y' to get:

$\frac{1}{y} \frac{dy}{dt} =27t^8$

Multiply both sides by 'dt' to get:

$\frac{1}{y}dy =27t^8dt$

Integrate both sides. Both sides will produce an integration constant, but I will merge them together into a single integration constant on the right side:

$\int\limits {\frac{1}{y} } \, dy=\int\limits {27t^8} \, dt$

$ln(y)=27(\frac{1}{9} t^9)+C$

$ln(y)=3t^9+C$

We want to cancel the natural log in order to isolate our function 'y'. We can do this by using 'e' since it is the inverse of the natural log:

$e^l^n^(^y^)=e^(^3^t^{^9} ^+^C^)$

$y=e^(^3^t^{^9} ^+^C^)$

We can take out the 'C' of the exponential using a rule of exponents. Addition in an exponent can be broken up into a product of their bases:

$y=e^(^3^t^{^9}^)e^C$

The term e^C is just another constant, so with impunity, I can absorb everything into a single constant:

$y=Ce^(^3^t^{^9}^)$

To check the answer by differentiation, you require the chain rule. Differentiating an exponential gives back the exponential, but you must multiply by the derivative of the inside. We get:

$\frac{d}{dx} (y)=\frac{d}{dx}(Ce^(^3^t^{^9}^))$

$\frac{dy}{dx} =(Ce^(^3^t^{^9}^))*\frac{d}{dx}(3t^9)$

$\frac{dy}{dx} =(Ce^(^3^t^{^9}^))*27t^8$

Now check if the derivative equals the right side of the original differential equation:

$(Ce^(^3^t^{^9}^))*27t^8=27t^8*y(t)$

$Ce^(^3^t^{^9}^)*27t^8=27t^8*Ce^(^3^t^{^9}^)$

QED

I unfortunately do not have enough room for your second question. It is the exact same type of differential equation as the one solved above. The only difference is the fractional exponent, which would make the problem slightly more involved. If you ask your second question again on a different problem, I'd be glad to help you solve it.

7 0

2 years ago