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alexdok [17]
3 years ago
15

Which is the best estimate of each percent? 48% of 60

Mathematics
2 answers:
melamori03 [73]3 years ago
7 0

Answer:

28.8\:\: \mathrm{or}\:\: 28\frac{4}{5}

Step-by-step explanation:

48% of 60

\frac{48}{100} \times \frac{60}{1}

Cross divide; cancel the zeros in 100 and 60

\frac{48}{10} \times \frac{6}{1}

Divide 10 and 6 by 2

10 ÷ 2 = 5

6 ÷ 2 = 3

\frac{48}{5} \times \frac{3}{1}

Simplify

48 × 3 = 144

5 × 1 = 5

\frac{144}{5}

Simplify

\frac{144}{5} = 28.8\:\: \mathrm{or}\:\: 28\frac{4}{5}

netineya [11]3 years ago
4 0
28.80 is the answer so of= x so yea
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Determine the equation of the line that passes through the points (-1 , 10) and (2,4)
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Given:

The two points are (-1,10) and (2,4).

To find:

The equation of line which passes though the given points.

Solution:

If a line passes through two points, then the equation of line is

y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)

The line passes through (-1,10) and (2,4). So, the equation of line is

y-10=\dfrac{4-10}{2-(-1)}(x-(-1))

y-10=\dfrac{-6}{2+1}(x+1)

y-10=\dfrac{-6}{3}(x+1)

y-10=-2(x+1)

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y-10=-2x-2

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Answer:

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Step-by-step explanation:

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Daily high temperatures in St. Louis for the last week were as​ follows: 95​, 92​, 93​, 92​, 95​, 90​, 90 ​(yesterday). ​a) The
hichkok12 [17]

Answer:

a) T = 91.7 degrees

b) T = 90 degrees

c) MAD = 1.9

d) MSE = 5.05

Step-by-step explanation:

Given:

- Daily high temperatures in St. Louis for the last week were as​ follows:

                                   95​, 92​, 93​, 92​, 95​, 90​, 90

Find:

a) Forecast the high temperature today, using a 3-day moving average.

b) Forecast the high temperature today, using a 2-day moving average.

c) Calculate the mean absolute deviation based on a 2-day moving average, covering all days in which you can have a forecast and an actual temperature.

d) The mean squared error for the​ 2-day moving average​

Solution:

a)

- The set of 3 day moving average is as follows:

4.   (95 + 92 + 93) ÷ 3 = 93.33⁰C

5.  (92 + 93 + 92) ÷ 3 = 92.33⁰C

6.  (93 + 92 + 95) ÷ 3 = 93.33⁰C

7.  (92 + 95 + 90) ÷ 3 = 92.33⁰C

8.  (95 + 90 + 90) ÷ 3 = 91.667⁰C

- Now use these points on excel sheet to forecast the temperature for today. The line of best fit is given:

T = 91.7 degrees

b)

- The set of 2 day moving average is as follows:

3.   (95 + 92) ÷ 2 = 93.5⁰C

4.  (95 + 93) ÷ 2 = 92.5⁰C

5.  (93 + 92) ÷ 2 = 92.5⁰C

6.  (92 + 95) ÷ 2 = 93.5⁰C

7.  (95 + 90) ÷ 2 = 92.5⁰C

8. (90 + 90) ÷ 2 = 90⁰C

- Now use these points on excel sheet to forecast the temperature for today. The line of best fit is given:

T = 90 degrees

c)

                             Error             Error^2

3.   93.5⁰C            0.5                  0.25

4.   92.5⁰C            0.5                  0.25

5.   92.5⁰C            2.5                  6.25

6.   93.5⁰C            3.5                  12.25

7.   92.5⁰C            2.5                  6.25

8.   90⁰C

- The mean absolute deviation as follows:

                              MAD = Sum of all errors  / 5

                              MAD = (0.5+0.5+2.5+3.5+2.5)  / 5

                              MAD = 1.9

d)

- The mean squared error deviation as follows:

                              MSE = Sum of all error^2  / 5

                              MSE = (0.25+0.25+6.25+12.25+6.25)  / 5

                              MSE = 5.05

4 0
3 years ago
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