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3 years ago

7. The ____ is a device that connects a stationary object to a fall restraint vest.

2 answers:

7 0

I’d say it’s C. lanyard because “ a safety lanyard connects a harness to a secure “ according to www.safetyliftinggear.com

swat323 years ago

7 0

Explanation:

Here is my question

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Consider the formation of p-nitrophenol from p-nitrophenyl trimethyl acetate. The process is known as enzymatic hydrolysis and i

solniwko [45]

Solution :

cs=zeros(9001);

ca=zeros(9001);

cp=zeros(9001);

psi=zeros(9001);

t=[0:0.1:900];

cs(1)=0.5;

ce(1)=0.001;

cp(1)=0;

ca(1)=0;

psi(1)=0;

for i=1:1:9000

cs(i+1)=cs(i)-0.1*((0.015*cs(i))/(5.53+cs(i)));

cp(i+1)=cp(i)+0.1*((0.015*cs(i))/(5.53+cs(i))-0.0026*cp(i));

ca(i+1)=ca(i)+0.1*0.0026*cp(i);

psi(i+1)=((cp(i+1)-cp(i)))/((cs(i)-cs(i+1)));

end

plot(t,cs,t,cp,t,ca);

plot(t,psi);

6 0

3 years ago

A light train made up of two cars is traveling at 90 km/h when the brakes are applied to both cars. Know that car A has a mass o

posledela

Answer:

a) $d=236.280\,m$ , b) $F_{coupling} = -8848\,N$ The real force has the opposite direction.

Explanation:

a) Let assume that train moves on the horizontal ground. An equation for the distance travelled by the train is modelled after the Principle of Energy Conservation and Work-Energy Theorem:

$K_{A} = W_{brake}$

$\frac{1}{2}\cdot m_{train} \cdot v^{2} = F_{brakes}\cdot d$

$d = \frac{m_{train}\cdot v^{2}}{2\cdot F_{brakes}}$

$d = \frac{(51000\,kg)\cdot [(90\,\frac{km}{h} )\cdot (\frac{1000\,m}{1\,km} )\cdot (\frac{1\,h}{3600\,s} )]^{2}}{2\cdot (82000\,N)}$

$d=194.360\,m$

b) The acceleration experimented by both trains are:

$a = -\frac{v_{o}^{2}}{2\cdot d}$

$a = -\frac{[(90\,\frac{km}{h} )\cdot (\frac{1000\,m}{1\,km} )\cdot (\frac{1\,h}{3600\,s})]^{2}}{2\cdot (194.360\,m)}$

$a = -1.608\,\frac{m}{s^{2}}$

The coupling force in the car A can derived of the following equation of equilibrium:

$\Sigma F = F_{coupling} - F_{brakes} = m_{A}\cdot a$

The coupling force between cars is:

$F_{coupling} = m_{A}\cdot a + F_{brakes}$

$F_{coupling} = (31000\,kg)\cdot(-1.608\,\frac{m}{s^{2}} )+41000\,N$

$F_{coupling} = -8848\,N$

The real force has the opposite direction.

8 0

3 years ago

A coil consists of 100 turns of wire wrapped around a square frame of sides 0.25 m. The coil is centered at the origin with each

jenyasd209 [6]

Find solution in attachments below

5 0

3 years ago

The real power delivered by a source to two impedances, ????1=4+????5⁡Ω and ????2=10⁡Ω connected in parallel, is 1000 W. Determi

kirza4 [7]

Answer:

The question is incomplete, below is the complete question

"The real power delivered by a source to two impedance, Z1=4+j5⁡Ω and Z2=10⁡Ω connected in parallel, is 1000 W. Determine (a) the real power absorbed by each of the impedances and (b) the source current."

answer:

a. 615W, 384.4W

b. 17.4A

Explanation:

To determine the real power absorbed by the impedance, we need to find first the equivalent admittance for each impedance.

recall that the symbol for admittance is Y and express as

$Y=\frac{1}{Z}$