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Snowcat [4.5K]
3 years ago
6

Zona intermedia de pozos Y Efecto de inavasion

Engineering
1 answer:
dlinn [17]3 years ago
5 0

so the answer is f because your a faliure so get out of here you fatty

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Technician A says high resistance causes an increase in current flow. Technician B says a higher than
Kryger [21]

The correct statement is: a higher than a normal voltage drop could indicate high resistance. Technician B is correct.

<h3>Ohm's law</h3>

Ohm's law states that the current flowing through a metallic conductor is directly proportional to the voltage provided all physical conditions are constant. Mathematically, it is expressed as

V = IR

Where

V is the potential difference

I is the current

R is the resistance

<h3>Technician A</h3>

High resistance causes an increase in current flow

V = IR

Divide both side by I

R = V / I

Thus, technician A is wrong as high resistance suggest low current flow

<h3>Technician B</h3>

Higher than normal voltage drop could indicate high resistance

V = IR

Thus, technician B is correct as high voltage indicates high resistance

<h3>Conclusion </h3>

From the above illustration, we can see that technician B is correct

Learn more about Ohm's law:

brainly.com/question/796939

8 0
2 years ago
Low-level coding means that...
svet-max [94.6K]

Answer:

a.) a component item is coded at the lowest level at which it appears in the BOM structure is the correct answer.

Explanation:

  • Low-level coding is a kind of programming language used in BOM structures and it carries basic commands that are identified by a computer.
  • The two types of low-level coding are
  • Assembly language.
  • machine language.
  • The advantages of using low-level coding are programs develop by using low-level code are very memory effective and quick and there no need to use interpreters for the conversion of the source to machine code.
7 0
3 years ago
For a turning operation, you have selected a high-speed steel (HSS) tool and turning a hot rolled free machining steel. Your dep
Alisiya [41]

Answer:

MRR = 1.984

Explanation:

Given that                              

Depth of cut ,d=0.105 in

Diameter D= 1 in

Speed V= 105 sfpm

feed f= 0.015 ipr

Now  the metal   removal  rate   given as

MRR= 12 f V d

d= depth of cut

V= Speed

f=Feed

MRR= Metal removal rate

By putting the values

MRR= 12 f V d

MRR = 12 x 0.015 x 105 x 0.105

MRR = 1.984

Therefore answer is -

1.944

8 0
2 years ago
Determine the percent increase in the nominal moment capacity of the section in Problem 2 when including compression steel at to
sergejj [24]

Explanation:

Please kindly share your problem two with us as to know the actual problem we are dealing with, the question looks incomplete

5 0
3 years ago
Air in a piston–cylinder assembly, initially at 3 bar, 142 K, and a volume of 2 m3. The air undergoes a process to a state where
Archy [21]

Answer:

mass of the air = 14.62kg

Workdone = 415.88 kJ

Heat transfer = 415.88 kJ

Explanation:

Please find the attached files for the solution

6 0
3 years ago
Read 2 more answers
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