Answer:
Problem B: x = 12; m<EFG = 48
Problem C: m<G = 60; m<J = 120
Step-by-step explanation:
Problem B.
Angles EFG and IFH are vertical angles, so they are congruent.
m<EFG = m<IFH
4x = 48
x = 12
m<EFG = m<IFH = 48
Problem C.
One angle is marked a right angle, so its measure is 90 deg.
The next angle counterclockwise is marked 30 deg.
Add these two measures together, and you get 120 deg.
<J is vertical with the angle whose measure is 120 deg, so m<J = 120 deg.
Angles G and J from a linear pair, so they are supplementary, and the sum of their measures is 180 deg.
m<G = 180 - 120 = 60
Answer:
7.) 16.7
Step-by-step explanation:
7). First you have to find the length of the line with the triangle that is at a 90 angle with the longest side of the triangle
Using the pythagrorem theorem a² + b² = c²
4² + b² = 5²
b² = 5² - 4²
b² = 25 - 16
b² = 9
√b² =√9
b = 3
next you do the same thing to find the missing segment of the longest side
3² + b² = 13²
b² = 169 - 9
b² = 160
b = √160 or ≈ 12.7
12.7 + 4 = 16.7
so 16.7 is the length of that side
Answer:
i think the second one
Step-by-step explanation:
i think it would be the smartest thing to pick
Answer:
51
Step-by-step explanation:
