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just olya [345]
3 years ago
13

Helpp i have 12 minutes

Mathematics
2 answers:
s2008m [1.1K]3 years ago
8 0
924.8 or 925


Mark brainliest please


Hope this helps you
Lemur [1.5K]3 years ago
7 0

Answer:

the answer is 924.8 round it up and you get 925

Step-by-step explanation:

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-8-5b+7+5b
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Please help me solve this
seropon [69]

9514 1404 393

Answer:

  103°

Step-by-step explanation:

The law of sines tells you ...

  sin(C)/c = sin(A)/a

  sin(C) = (c/a)sin(A)

  C = arcsin(c/a·sin(A)) = arcsin(37/19·sin(30°)) ≈ 180° -76.8° ≈ 103°

Obtuse angle C is about 103°.

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tigry1 [53]

Answer:

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Step-by-step explanation:

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3 years ago
Who wrote down the equation for the law of gravitation?
aalyn [17]
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7 0
3 years ago
8. How many ways can a committee of 5 students be chosen from a student council of 30 students? Is the order in which the member
tankabanditka [31]

Answer: A committee of 5 students can be chosen from a student council of 30 students in 142506 ways.

No , the order in which the members of the committee are chosen is not  important.

Step-by-step explanation:

Given : The total number of students in the council = 30

The number of students needed to be chosen = 5

The order in which the members of the committee are chosen does not matter.

So we Combinations (If order matters then we use permutations.)

The number of combinations of to select r things of n things = ^nC_r=\dfrac{n!}{r!(n-r)!}

So the number of ways a committee of 5 students can be chosen from a student council of 30 students=^{30}C_5=\dfrac{30!}{5!(30-5)!}

=\dfrac{30\times29\times28\times27\times26\times25!}{(120)\times25!}=142506

Therefore , a committee of 5 students can be chosen from a student council of 30 students in 142506 ways.

4 0
3 years ago
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