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3 years ago

PLEASE HELP HELP HELP

Mathematics

1 answer:

kobusy [5.1K]3 years ago

4 0

Answer:

5 ( y + 3 ) = 4

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Find (8.4×108) ÷ (1.2×103). Express your answer in scientific notation.

kvv77 [185]

Answer: 7.33980582 x 10^0

Step-by-step explanation:

Move the decimal so there is one non-zero digit to the left of the decimal point. The number of decimal places you move will be the exponent on the 10. The sign of the exponent will depend on the direction you are moving the decimal.

8 0

3 years ago

Read 2 more answers

Simplify the expression<br> 70.7-5.76

Romashka-Z-Leto [24]

Answer:

64.94

Explanation

You arrange the numbers in such a way, to be in line with their decimal points like this:

70.7

-5.76

Then you subtract. Notice that on top of the 6 is nothing which is equal to 0

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3 years ago

A supermarket sells corn flakes for $3.60 per box. If the markup on the cereal is 30%, how much did the supermarket pay for each

Alexxx [7]

Answer: 70

Step-by-step explanation:

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3 years ago

Which of the following terms correctly describes 4 : 1? A- Ratio B- Fraction C-Percent D- Factor

kvv77 [185]

Sabrehalrubeai,

In order to find the correct answer to this question we need to go over all of the options to see which one is the correct answer.

Ratio: $6 : 9$ <---- Your answer....
Fraction: $\frac{6}{9}$
Percent: $35%$
Factor: $4 \times 3 = 12$

Therefore your answer is option A "ratio."

Hope this helps!

6 0

3 years ago

In 1980 (before the era of in-vitro fertilization), there were 3,612,258 births in the United States (according to the U.S. Cens

scoray [572]

Answer:

There was a 1.93% probability of having multiples (twins or more) in 1980.

Step-by-step explanation:

There were 3,612,258 births in the US in 1980.

Of those,

68339 + 1337 = 69676 were multiplies.

What was the probability of having multiples (twins or more) in 1980?

$P = \frac{69676}{3612258} = 0.0193$

There was a 1.93% probability of having multiples (twins or more) in 1980.

8 0

3 years ago