What is a benefit of an account with interest?

You are trying to troubleshoot a desktop power supply issue using a voltmeter. Which of the following options are the MOST commo

vredina [299]

Answer:

The correct answers are: (A) +/- 5V and (B) +/- 12V

Explanation:

First at all, the purpose of the power supply is transforming from AC (Alternating Current) to DC (Direct Current) for use this energy in chips and electronics devices that consume this type of power. Usually the most common DC voltage for electronics is 5V but in your CPU you also have other devices that might going to need more voltage like fan or hard drives thats ´s why 12V is an also an option. Now some other devices are going to need negative sources such -5V or -12V as well.

7 0

2 years ago

Alexis received paychecks from both her jobs and she would like to deposit them. One check is for $62.88 and the other is $523.2

Karolina [17]

Answer:

something :}

Explanation:

have a good day

8 0

2 years ago

A computer retail store has 15 personal computers in stock. A buyer wants to purchase 3 of them. Unknown to either the retail st

Dima020 [189]

Answer:

a. 1365 ways

b. Probability = 0.4096

c. Probability = 0.5904

Explanation:

Given

PCs = 15

Purchase = 3

Solving (a): Ways to select 4 computers out of 15, we make use of Combination formula as follows;

$^nC_r = \frac{n!}{(n-r)!r!}$

Where $n = 15\ and\ r = 4$

$^{15}C_4 = \frac{15!}{(15-4)!4!}$

$^{15}C_4 = \frac{15!}{11!4!}$

$^{15}C_4 = \frac{15 * 14 * 13 * 12 * 11!}{11! * 4 * 3 * 2 * 1}$

$^{15}C_4 = \frac{15 * 14 * 13 * 12}{4 * 3 * 2 * 1}$

$^{15}C_4 = \frac{32760}{24}$

$^{15}C_4 = 1365$

Hence, there are 1365 ways 

Solving (b): The probability that exactly 1 will be defective (from the selected 4)

First, we calculate the probability of a PC being defective (p) and probability of a PC not being defective (q)

From the given parameters; 3 out of 15 is detective;

So;

$p = 3/15$

$p = 0.2$

$q = 1 - p$

$q = 1 - 0.2$

$q = 0.8$

Solving further using binomial;

$(p + q)^n = p^n + ^nC_1p^{n-1}q + ^nC_2p^{n-2}q^2 + .....+q^n$

Where n = 4

For the probability that exactly 1 out of 4 will be defective, we make use of

$Probability = ^nC_3pq^3$

Substitute 4 for n, 0.2 for p and 0.8 for q

$Probability = ^4C_3 * 0.2 * 0.8^3$

$Probability = \frac{4!}{3!1!} * 0.2 * 0.8^3$

$Probability = 4 * 0.2 * 0.8^3$

$Probability = 0.4096$

Solving (c): Probability that at least one is defective;

In probability, opposite probability sums to 1;

Hence;

Probability that at least one is defective + Probability that at none is defective = 1

Probability that none is defective is calculated as thus;

$Probability = q^n$

Substitute 4 for n and 0.8 for q

$Probability = 0.8^4$

$Probability = 0.4096$

Substitute 0.4096 for Probability that at none is defective

Probability that at least one is defective + 0.4096= 1

Collect Like Terms

Probability = 1 - 0.4096

Probability = 0.5904

8 0

2 years ago

In Broadbent's filter model of attention, the stages of information processing occur in which order?

victus00 [196]

Answer:SENSORY STORE, FILTER, DETECTOR, STM.

Explanation:Donald Broadbent in 1958 stated one of the earliest theory of attention,he stated that physical features of messages are used to select one message for further processing and that all others are lost.This differs from inattentional blindness, which is when you focus hard on something and fail to notice unexpected things entering your visual area. He believes that

Information from all of the stimuli presented at any given time enters a sensory buffer with unlimited capacity.

3 0

3 years ago

There are two main types of hard drive available to a computer. State what they are and describe their use.

Gala2k [10]

Answer:

Hard disk drives (HDD), which use one or more rotating discs and rely on magnetic storage, and solid-state drives (SSD), which have no moving mechanical parts, but use flash memory like the kind found in USB flash drives.

Explanation:

6 0

2 years ago