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pshichka [43]
3 years ago
13

Mohan opened a Recurring deposit Account in a bank for five year and deposite 100 RS every month. If the rate of interest 6% per

annum them how much money will he get after 5 years.​​
Mathematics
1 answer:
pogonyaev3 years ago
6 0

Answer:

<u>☼︎</u><u>I</u><u>n</u><u>f</u><u>o</u><u>r</u><u>m</u><u>a</u><u>t</u><u>i</u><u>o</u><u>n</u><u> </u><u>P</u><u>r</u><u>o</u><u>v</u><u>i</u><u>d</u><u>e</u><u>d</u><u>:</u>

  • Mohan opened a Recurring deposit Account in a bank for five years

  • He deposited Rs.100 every month

  • Rate of interest is 6% per annum

<u>☼︎</u><u>W</u><u>hat we have to calculate :</u>

  • How much money will he get after 5 years?

<h2><u>☼︎</u><u>Using Formulas :</u></h2>

<u>☼︎</u><u>Maturity value:-</u>

\boxed{\sf{\longmapsto \: M.V. \: = \: P \times \: n \: + \: I }}

<h2><u>☼︎</u><u>Interest:-</u></h2>

\boxed{\sf{\longmapsto \: I\: = \: P \times \: \frac{n(n + 1)}{2 \times 12} \: + \: \dfrac{r}{100} }}

<u>☼︎</u><u>In both the formulas,</u>

  • P is Principal

  • n is number of months

  • r is rate of interest

<u>☼︎</u><u>Performing Calculations :</u>

Finding out the interest by substituting the values in the given formula of calculating the interest~

<u>☼︎</u><u>Number of months :</u>

<h3>☼︎We know that,</h3>

  • 1 year = 12 months

  • 5 years = 12 × 5 months

  • 5 years = 60 months

<u>☼︎</u><u>We have :</u>

  • P is 100

  • r is 6%

  • n is 60

<u>☼︎</u><u>Putting the values :</u>

\: \tt { \longmapsto \: I \ \: = \: 100 \times \dfrac{60(60 + 1)}{2 \times 12} \: \times \: \dfrac{6}{100} }

\: \sf{I \: = \:100 \times \dfrac{60(61)}{2 \times 12} \: \times \: \dfrac{6}{100} }

\: \sf{I \: = \:100 \times \dfrac{60 \times 61}{2 \times 12} \: \times \: \dfrac{6}{100} }

\: \sf{I \: = \: 100 \times \dfrac{3660}{24} \: \times \: \dfrac{6}{100} }

\: \sf{I \: = \: \dfrac{3660}{ \cancel{24}} \: \times \: \cancel {6}}:⟼I=243660×6

: \longmapsto \: \sf{I \: = \: \dfrac{3660}{4}}

: \longmapsto \: \sf{I \: = \: \cancel\dfrac{3660}{4}}

: \longmapsto \: \boxed{ \mathfrak \green{{I \: = \: 915} }}

<u>☼︎</u><u>Now, putting the values in formula of M.V. :</u>

<u>{ \underline {\rule{9cm}{0.3cm}}}</u>

... \: \sf{\longmapsto \: M.V. \: = \: 100 \: \times \: 60 + \: 915}

... \sf{  \longmapsto\: M.V. \: = \: 6000 + \: 915}:

... \longmapsto \: \boxed{\pink{\sf{M.V. \: = \mathfrak {6915}}}}:

\underline{\bf{Hence \: he \: would \: get \: Rs.6915 \: after \: 5 \: years}}

{ \underline {\rule{9cm}{0.3cm}}}

<h3>☼︎Additional<u> </u><u>I</u><u>n</u><u>f</u><u>o</u><u>r</u><u>m</u><u>a</u><u>t</u><u>i</u><u>o</u><u>n</u></h3>

Interest (I) received on maturity on the investment of Rs P per month at the rate of r % per annum for n months is

\bold{ \red{\boxed{\text{I} = \text{P} \times \dfrac{ \text{n(n + 1)}}{24} \times \dfrac{ \text{r}}{100} }}}

<u>Maturity Value (MV)</u>

 Received on maturity on the investment of Rs P per month at the rate of r % per annum for n months is also given by

\begin{gathered} \pink{\boxed{\rm{ MV \: = \: \text{P} \: + \: I \: }}} \\ \end{gathered}

{ \underline {\rule{9cm}{0.3cm}}}

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