Answer:
223 L
Explanation:
Step 1: Write the balanced equation.
2 LiOH + CO₂ = Li₂CO₃ + H₂O
Step 2: Calculate the moles corresponding to 440 g of LiOH
The molar mass of LiOH is 23.95 g/mol.
440 g × (1 mol/23.95 g) = 18.4 mol
Step 3: Calculate the moles of CO₂ that react with 18.4 moles of LiOH
The molar ratio of LiOH to CO₂ is 2:1. The reacting moles of CO₂ are 1/2 × 18.4 mol = 9.20 mol.
Step 4: Convert 20°C to Kelvin
K = °C + 273.15 = 20 + 273.15 = 293 K
Step 5: Convert 753 torr to atm
753 torr × (1 atm/760 torr) = 0.991 atm
Step 6: Calculate the volume of CO₂
We will use the ideal gas equation.
P × V = n × R × T
V = n × R × T / P
V = 9.20 mol × (0.0821 atm.L/mol.K) × 293 K / 0.991 atm
V = 223 L
