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fgiga [73]
3 years ago
7

An atom contains one proton , one electron, and one neutron. Which two particles are most similar in mass

Chemistry
2 answers:
ra1l [238]3 years ago
8 0

Answer:

proton and neutron

Explanation:

andrey2020 [161]3 years ago
3 0
Proton and neutron, which are both approximately 1 amu
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Sodium (chemical symbol Na) is atomic number 11 and is in the first column of the periodic table so it has one valence electron.
lisabon 2012 [21]
Na is cation so it loses electron to be positive and become stable losing one valence shells one electron so it's oxidation number is +1 ie A is correct
7 0
4 years ago
Read 2 more answers
44. Convert the following. Express your answers in
professor190 [17]

Answer:

A =  0.75 ×10² KJ.

B = 3.9 ×10³ dg

C = 0.22 × 10² μl.

Explanation:

A =  7.5 ×10⁴ j to kilo joules

7.5 ×10⁴ / 1000 = 0.75 ×10² KJ.

Joule is the smaller unit while kilo joule is the larger unit. One kilo joule equals to the thousand joule that's why we will divide the given value by 1000 in order to convert into KJ.

B = 3.9 ×10⁵ mg to decigrams.

3.9 ×10⁵ / 100 = 3.9 ×10³ dg

Decigram is larger unit while milligram is smaller unit. One decigram is equal to the 100 milligram. In order to convert the given value into  decigram we have to divide the value by 100.

C = 2.21 ×10⁻⁴ dL to micorliters

2.21 ×10⁻⁴ ×10⁵ = 0.22 × 10² μl.

Deciliter is bigger unit then micro liter . One deciliter equals to the 100000 micro liters. In order to convert the dL into micro liter we have to multiply the given value with 100000.

4 0
4 years ago
What does the symbol C p stand for?
Evgesh-ka [11]

Cp stands for specific heat.

8 0
3 years ago
Read 2 more answers
ubstance A undergoes a first order reaction A®B with a half-life, t½, of 20 min at 25 °C. If the initial concentration of A in a
Stells [14]

Answer : The concentration of A after 80 min is, 0.100 M

Explanation :

Half-life = 20 min

First we have to calculate the rate constant, we use the formula :

k=\frac{0.693}{t_{1/2}}

k=\frac{0.693}{20\text{ min}}

k=3.465\times 10^{-2}\text{ min}^{-1}

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant  = 3.465\times 10^{-2}\text{ min}^{-1}

t = time passed by the sample  = 80 min

a = initial amount of the reactant  = 1.6 M

a - x = amount left after decay process = ?

Now put all the given values in above equation, we get

80=\frac{2.303}{3.465\times 10^{-2}}\log\frac{1.6}{a-x}

a-x=0.100M

Therefore, the concentration of A after 80 min is, 0.100 M

3 0
3 years ago
How many formula units are in 0.96 moles of H2O
never [62]

Answer:

18.02 amu

Explanation:

6 0
3 years ago
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