Answer: 16.32 g of 
as excess reagent are left.
Explanation:
To calculate the moles :
According to stoichiometry :
2 moles of 
require = 1 mole of
Thus 0.34 moles of will require=
of
Thus is the limiting reagent as it limits the formation of product and is the excess reagent.
Moles of left = (0.68-0.17) mol = 0.51 mol
Mass of 
Thus 16.32 g of as excess reagent are left.
Transition metals usually
Answer:
Explanation:
Hello,
In this case, is possible to infer that the thermal equilibrium is governed by the following relationship:
Thus, both iron's and water's heat capacities are: 0.444 and 4.18 J/g°C respectively, so one solves for the mass of water as shown below:
Best regards.
Word equation - calcium + oxygen -> calcium oxide
Chemical equation - Ca + O2 -> CaO2
Hope this helps!
