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disa [49]
3 years ago
6

In an internal combustion engine, octane reacts with oxygen gas to produce carbon dioxide and water and a large amount of energy

.
a) What are the reactants?
b) What are the products?
c) Write a word equation to represent:
Chemistry
2 answers:
Maslowich3 years ago
7 0

Answer:

2 C8H18 + 25 O2 → 16 CO2 + 18 H2O.

Explanation:

sergij07 [2.7K]3 years ago
5 0

Answer:

When octane and oxygen gas are burned in our cars, carbon dioxide and water come out of the exhaust. The increase in carbon dioxide in the atmosphere is causing global warming. 4.

Explanation:

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Monica [59]

Answer:

1.25 g

Explanation:

.5^3 = 0.125

0.125*10 = 1.25 g

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3 years ago
What volume of hydrogen gas, when combined with nitrogen gas,
Westkost [7]

The volume of Hydrogen gas : 24 L

<h3>Further explanation</h3>

Given

16 L Ammonia(NH₃)

Required

The volume of Hydrogen gas

Solution

Reaction

N₂ + 3H₂ ⇒ 2NH₃

Avogadro's hypothesis:  

In the same T,P and V, the gas contains the same number of molecules  

So the ratio of gas volume will be equal to the ratio of gas moles  

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From the equation, mol ratio of H₂ : NH₃ = 3 : 2, so volume of H₂ :

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3 years ago
What was madame curry famous for
aksik [14]
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6 0
4 years ago
Read 2 more answers
g modenr vacuum pumps make it easy to attain pressures of the order of in the laboratory. at a preasusure of 6.75 atm and an ord
Ratling [72]

Answer:

Number of molecules = 1.8267×10^20

Explanation:

From the question, we can deuced that the gases behave ideally, the we can make use of the ideal gas equation, which is expressed below;

PV = nRT

where

P =pressure

V =volume

n = the number of moles

R is the gas constant equal to 0.0821 L·atm/mol·K

T is the absolute temperature

Given:

P = 6.75 atm;

T = 290.0 k,

; V = 1.07 cm³ = 0.001 L

( 6.75 atm)(0.00107 L) = n(0.0821 L·atm/mol·K)(290K)

n = 3.0335167*10^-4 moles

But there are 6.022×10²³ molecules in 1 mole,

Number of molecules = 1.8267×10^20

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4 years ago
What does the line if blue triangles mean on a weather map
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3 years ago
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