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Cerrena [4.2K]
3 years ago
10

Please help!!! due soon!

Chemistry
1 answer:
Veseljchak [2.6K]3 years ago
7 0

Answer:

Always stays the same.

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How many photons are produced in a laser pulse of 0.497 J at 469 nm?
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Question &gt; calculate the percent composition of each element in the following compounds
Lostsunrise [7]

Answer:

The percent composition of each element are :

1. <u>Th(SO4)2 :</u>

Th = 54.704%  ,  S =  15.119%  ,    O = 30.1759 %

<u>2.Ca3(PO4)2 </u>

Ca = 38.76%    ,   P = 19.97% ,       O = 41.265%

<u>3.C6H12O6</u>

C = 40.0%        ,   H = 6.72% ,         O = 53.29%

Explanation:

<u><em>Formula  calculate the percent composition</em></u>

% composition =\frac{mass\ of\ given\ element}{Molar\ mass}

Molar mass of Th(SO4)2 = Mass of Th + 2(mass of S) + 8(mass of O)

= 232.03 + 2(32.06) + 8(16)

=232.03 +64.12+128

= 424.16

% Th=\frac{mass\ of\ Th}{424.16}

=\frac{232.03}{424.16}

= 54.704%

% S=\frac{2(mass\ of\ S)}{424.16}

=\frac{64.12}{424.16}

= 15.119%

% O=\frac{8(mass\ of\ O)}{424.16}

= \frac{128}{424.16}

= 30.17%

2.Ca3(PO4)2

Molar mass of Ca3(PO4)2 = 3(Mass of Ca) + 2(mass of P) + 8(mass of O)

= 3(40) + 2(30 .9) + 8(16)

= 120 + 61.8 + 128

=310.176

% Ca =\frac{3(mass\ of\ Ca)}{310.176}

=\frac{120}{424.16}

38.76%

% P=\frac{2(mass\ of\ P)}{310.176}

=\frac{61.8}{310.176}

= 19.97%

% O=\frac{8(mass\ of\ O)}{310.176}

=\frac{128}{424.16}

= 41.26 %

3.

C6H12O6

Molar mass of C6H12O6  = 6(Mass of C) + 12(mass of O) + 6(mass of O)

= 6(12) + 12(1) + 6(15.99)

=180

% O=\frac{6(mass\ of\ O)}{180}

=\frac{95.94}{180}

= 53.28%

% C=\frac{6(mass\ of\ C)}{180}

% C=\frac{72}{180}

= 40%

% H=\frac{12(mass\ of\ C)}{180}

=\frac{(12}{180}

= 6.713%

8 0
3 years ago
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