<span>E=hν</span> where E is the energy of a single photon, and ν is the frequency of a single photon. We recall that a photon traveling at the speed of light c and a frequency ν will have a wavelength λ given by <span>λ=<span>cν</span></span>λ will have an energy given by <span>E=<span><span>hc</span>λ</span></span><span>λ=657</span> nm. This will be <span>E=<span><span>(6.626×<span>10<span>−34</span></span>)(2.998×<span>108</span>)</span><span>(657×<span>10<span>−9</span></span>)</span></span>=3.0235×<span>10<span>−19</span></span>J</span>
So we now know the energy of one photon of wavelength 657 nm. To find out how many photons are in a laser pulse of 0.363 Joules, we simply divide the pulse energy by the photon energy or <span>N=<span><span>E<span>pulse </span></span><span>E<span>photon</span></span></span>=<span>0.363<span>3.0235×<span>10<span>−19</span></span></span></span>=1.2×<span>1018</span></span>So there would be <span>1.2×<span>1018</span></span><span> photons of wavelength 657 nm in a pulse of laser light of energy 0.363 Joules.</span>
Answer:
I believe it is B (if you get it wrong it's my fault)
A difference between plant cells and animal cells is that most animal cells are found whereas most plant cells are rectangular. Plant cells have rigid cell wall that surrounds the cell membrane.animals do not have a cell wall
They have the same number of protons in the nucleus.
Answer:
The percent composition of each element are :
1. <u>Th(SO4)2 :</u>
Th = 54.704% , S = 15.119% , O = 30.1759 %
<u>2.Ca3(PO4)2 </u>
Ca = 38.76% , P = 19.97% , O = 41.265%
<u>3.C6H12O6</u>
C = 40.0% , H = 6.72% , O = 53.29%
Explanation:
<u><em>Formula calculate the percent composition</em></u>

Molar mass of Th(SO4)2 = Mass of Th + 2(mass of S) + 8(mass of O)
= 232.03 + 2(32.06) + 8(16)
=232.03 +64.12+128
= 424.16


= 54.704%


= 15.119%


= 30.17%
2.Ca3(PO4)2
Molar mass of Ca3(PO4)2 = 3(Mass of Ca) + 2(mass of P) + 8(mass of O)
= 3(40) + 2(30 .9) + 8(16)
= 120 + 61.8 + 128
=310.176


38.76%


= 19.97%


= 41.26 %
3.
C6H12O6
Molar mass of C6H12O6 = 6(Mass of C) + 12(mass of O) + 6(mass of O)
= 6(12) + 12(1) + 6(15.99)
=180


= 53.28%


= 40%


= 6.713%