D because the two sides have to be larger than the hypotenuse when added
Answer:
the perimeter is simply 2L + 2W
So lengthy 8.3
2(8.3) + 2(w) =22.4
16.6=2(w) =22.4
2(w) = 5.8
w = 5.8 divide by 2
The width is 2.9
Answer:
Area shaded portion = 16/3 π - 8√3
Step-by-step explanation:
The shaded portion consists of 2 equal segment
∵ Two circles have the same radii = 4
∵ The the length of the common chord of the two circles = 4
∴ The central angle of each segment = π/3 (60° equilateral Δ)
∵ Area segment = area sector - area Δ
∵ Area sector = 1/2 r²Ф = 1/2 × (4)² × π/3 = 8/3 π
∵ Area Δ = 1/4 s² √3 = 1/4 × (4)² × √3 = 4√3
∴ Area segment = 8/3 π - 4√3
∴ Area shaded portion = 2(8/3 π - 4√3) = 16/3 π - 8√3
6x-1 because you combine like terms 4x+2x=6x and then -4+3=-1
3y + 2 + 2y + 7 = 10y - 11
5y + 9 = 10y - 11
20 = 5y
4 = y
RS = 14
ST = 15
RT = 29