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Fudgin [204]
3 years ago
11

.

Mathematics
1 answer:
vova2212 [387]3 years ago
4 0
It would be the last one, to inform readers about a topic using facts and details.
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Use technology to graph function h. Then use the graph to evaluate the function.
Gemiola [76]
It will be 4836 = a’n so do it in classssss
8 0
3 years ago
The angle θ lies in quadrant ii. cos θ = -2/3 what is tan θ?
Alina [70]

Answer:

-√5/2

Explanation: I took the quiz.

5 0
3 years ago
Skye had 12 1/4 meters of ribbon. She used 2/3 of it to wrap a present and 1/2 of the remainder on a craft project. How many met
LenaWriter [7]

Answer:

She has 2 1/24 meters of ribbon

Step-by-step explanation:

Skye has 12 1/4 meters of ribbon, and she uses 2/3 of that.

To know how much she uses we have to multiply the total by the fraction she uses:

12 1/4 * 2/3,

12 1/4 is the same as 49/4, so we can solve by multiplying the nominators and denominators:

49/4 * 2/3 = 49/6;

So she used 49/4 meters of ribbon or 8.167 m.

Now we are going to see how much ribbon is left by subtracting from the total what she used:

12 1/4 - 49/4 = 49/12 meters that she has left.

And out of those she uses 1/2, so we are going to multiply what she has left by 1/2:

49/12 * 1/2 = 49/24 = 2 1/24 = 2.04167 meters that she used of the remaining.

And because she used half she still has the other half of the remaining:

2 1/24 or 2.94167 meters.

8 0
3 years ago
The position of a particle moving in a straight line at any time t is x(t) = 2t^2 + 6t + 5. What is the acceleration of the part
grandymaker [24]

Answer:

The acceleration of the particle at any time t

a = 4\ m/s^{2}

Step-by-step explanation:

Given:

The position of a particle moving in a straight line at any time t is.

x(t) = 2t^{2} + 6t + 5

The velocity of the particle v = \frac{d(x)}{d(t)}

v = \frac{d}{d(t)}(2t^{2} + 6t + 5)

v= 2\times 2t + 6

v= 4t + 6

So the velocity of the particle v= (4t + 6)\ m/s

The acceleration of the particle a = \frac{d(v)}{d(t)}

a = \frac{d}{d(t)}(4t + 6)

a = 4\ m/s^{2}

In this condition the acceleration does not depending upon the time, so the acceleration is constant

Therefore the acceleration of the particle at any time t a = 4\ m/s^{2}

7 0
3 years ago
What is the square root of -16
ad-work [718]

Answer:

The square root of -16 is 4 i

3 0
3 years ago
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