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omeli [17]
3 years ago
5

Which type of network cover a large geographical area and usually consists of several smaller networks, which might use differen

t computer platforms and network technologies.​
Computers and Technology
1 answer:
tiny-mole [99]3 years ago
7 0

Answer:

WAN

Explanation:

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Q.No.3 b. (Marks 3)
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3 years ago
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3 years ago
Write code for a function with the following prototype: /* Addition that saturates to TMin or TMax */ int saturating_add(int x,
Kazeer [188]

Answer:

See explaination

Explanation:

program code.

/* PRE PROCESSOR DIRECTIVES */

#include<stdio.h>

/* PRE-DEFINED VALUES FOR TMAX AND TMIN */

#define TMax 2147483647

#define TMin (-TMax -1)

/* saturating_add(int,int) METHOD IS CALLED HERE */

int saturating_add(int firstNumber, int secondNumber)

{

/*

FOR BETTER UNDERSTANDING, LETS TAKE TEST CASE,

WHERE firstNumber = 5 AND secondNumber = 10

*/

int w = sizeof(firstNumber) << 3;

/*

sizeof(firstNumber) VALUE IS 4, SO USING BINARY LEFT SHIFT OPERATOR TO THREE PLACES,

WE HAVE NOW VALUE 32, ASSIGNED TO w

*/

/* ADDITION IS CALCULATED => 15 */

int addition = firstNumber + secondNumber;

/*

MASK INTEGER VARIABLE IS TAKEN

mask BIT IS LEFT SHIFTED TO 31 PLACES => 2^31 IS THE NEW VALUE

*/

int mask = 1 << (w - 1);

/* FIRST NUMBER MOST SIGNIFICANT BIT IS CALCULATED BY USING AND OPERATOR */

int msbFirstNumber = firstNumber & mask;

/* SECOND NUMBER MOST SIGNIFICANT BIT IS CALCULATED BY USING AND OPERATOR */

int msbSecondNumber = secondNumber & mask;

/* MOST SIGNIFICANT BIT OF ADDITION IS CALCULATED BY USING AND OPERATOR */

int msbAddition = addition & mask;

/* POSITIVE OVERFLOW IS DETERMINED */

int positiveOverflow = ~msbFirstNumber & ~msbSecondNumber & msbAddition;

/* NEGATIVE OVERFLOW IS DETERMINED */

int negativeOverflow = msbFirstNumber & msbSecondNumber & !msbAddition;

/* THE CORRESPONDING VALUE IS RETURNED AS PER THE SATURATING ADDITION RULES */

(positiveOverflow) && (addition = TMax);

(negativeOverflow) && (addition = TMin);

return addition;

}

/* MAIN FUNCTION STARTS HERE */

int main(){

/* TEST CASE */

int sum = saturating_add(5, 10);

/* DISPLAY THE RESULT OF TEST CASE */

printf("The Sum Is : %d\n\n",sum);

}

7 0
3 years ago
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