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BigorU [14]
3 years ago
12

Add a kennel there are five cats and six dogs what are the correct ratios

Mathematics
1 answer:
hodyreva [135]3 years ago
6 0

Answer:

6:5

Step-by-step explanation:

I am thinking it would be 6:5 because you have 6 dogs, and 5 cats. So, you could think of it as for every 6 dogs you have 5 cats at the kennel.

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Two cards are drawn at random without replacement from a deck of 52 playing cards. If the first card chosen is a King, what is t
gulaghasi [49]

Answer:

p=0.05882

Step-by-step explanation:

Probability is the likelihood of an event occurring.

-A standard deck of cards has 4 kings.

#After one card is removed, 51 remains of which 3 are kings:

P(king)=\frac{3}{51}\\\\=0.05882

Hence, the probability that the second card is king is 0.05882

3 0
3 years ago
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Find the value of 21 + 4(32 - 5).<br><br> 37<br> 25<br> 100
bija089 [108]
21+4(32-5)=448


I think it’s 448
4 0
3 years ago
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Omani drives 66 miles in 1.5 hours
Burka [1]

Answer:

25.6 km/h

Step-by-step explanation:

Omani:

First, 1.5 hours = 1 hour and 30 minutes

and 66 miles = 105.6 km (66 x 1.6 = 105.6)

105.6 / 1.5 = 70.4 km/h

Omani's speed is 70.4 km/h

Adedi:

1 hour and 15 minutes is 1.25 hours

she drives 56 km in 1.25 hours

So 56 / 1.25 = 44.8 km/h

Adedi's speed is 44.8 km/h

Difference:

70.4 - 44.8 = 25.6 km/h

Omani is faster than Adedi with 25.6 km/h

8 0
3 years ago
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A conical vessels with base radius 5 cm and height 24cm is full of water this water is emptied into a cylindrical vessel of base
Aliun [14]

Answer:

2\ cm

Step-by-step explanation:

We\ are\ given\ that,\\Radius\ of\ the\ conical\ vessel=5\ cm\\Height\ of\ the\ conical\ vessel=24\ cm\\Hence,\\As\ we\ know\ that,\\Volume\ of\ a\ cone=\frac{1}{3}\pi r^2h\\Hence,\\The\ volume\ of\ the\ conical\ vessel=\frac{1}{3}\pi (5)^224=  \frac{1}{3}\pi 25*24=200\pi \\Hence,\\The\ volume\ of\ the\ conical\ vessel=The\ amount\ of\ water\ filled\ in\ it\\Hence,\\The\ amount\ of\ water\ filled\ in\ the\ conical\ vessel=200\pi\\Lets\ consider\ the\ cylindrical\ vessel:\\Volume\ of\ a\ cylinder=\pi r^2h

As\ we\ are\ not\ said\ that\ the\ cylindrical\ vessel\ was\ empty,\ let\ its\ initial\\ height\ be\ h_1\\Radius\ of\ the\ Cylindrical\ vessel=10\ cm\\Initial\ height\ of\ the\ cylindrical\ vessel=h_1\\Initial\ volume\ of\ the\ cylindrical\ vessel=\pi *10^2*h_1=100h_1\pi \\Initial\ amount\ of\ water\ in\ the\ cylindrical\ vessel=100h_1\pi \\Hence,\\Final\ amount\ of\ water\ in\ the\ cylindrical\ vessel=Final\ amount\ of\ water\\ in\ the\ cylindrical\ vessel +Amount\ of\ water\ in\ conical\ vessel

Hence,\\Final\ amount\ of\ water\ in\ the\ cylindrical\ vessel=100h_1\pi +200\pi \\Now,\\Let\ the\ final\ height\ be\ h_2\\Hence,\\Final\ amount\ of\ water\ in\ the\ cylindrical\ vessel=\pi *10^2*h_2=100h_2\pi \\Hence,\\100h_2\pi =100h_1\pi +200\pi \\Hence,\\100h_2=100h_1+200\\100h_2-100h_1=200\\100(h_2-h_1)=200\\h_2-h_1=2\\Hence,\\As\ the\ rise\ in\ level\ is\ the\ difference\ between\ the\ initial\ and\ final\\ heights:\\The\ rise\ in\ level\ of\ water=2\ cm

8 0
3 years ago
-2x+3y=-12 2x+y=4 After adding the two equations to eliminate x you are left with 4y=-8 Solve for y: y =
Marina86 [1]

Answer:

y = -2

Step-by-step explanation:

y = -8/4 = -2

3 0
3 years ago
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