Answer:
Solution given:
The volume of two similar solids are 128 m³
and 250 m³.
surface area of larger solid is 250m²
<u>let</u><u> </u><u>surface</u><u> </u><u>area</u><u> </u><u>of</u><u> </u><u>smaller</u><u> </u><u>solid</u><u> </u><u>be</u><u> </u><u>x</u><u>.</u>
<u>Since</u><u> </u><u>they</u><u> </u><u>are</u><u> </u><u>similar</u>

x=128
the surface are of the
smaller solid is 128m²
A) 24
24 x 10
b)
103
103 x 10
C) 35
35 x 10
D) 73
73 x 10
E) 28
28 x 10
F) 41
41 x 10
Answer:
No solution
Step-by-step explanation:
There is no solution to the system of equations y=3x+2 and 6x-2y=8, meaning that they are parallel to each other on a graph, with no points ever intersecting on each other's lines.
The answer is B) <span>(q - 2)(2p - 5r)
</span>2pq - 5qr + 10r - 4p = 2pq - 4p - 5qr + 10r
= 2pq - 4p - (5qr - 10r)
= 2p(q - 2) - 5r(q - 2)
= (q - 2)(2p - 5r)