Is the answer 44 feet wide? What I did was draw a rectangle an label both widths as 6, that equals 12. Then I subtracted 12 from 96 and got 84 and in order to only get one side length I divided it by 2 and got 42. Next I added 2 to that because the width of one side took up one foot and so did the other side so yeah. I'm just guessing.
so, we know both the rectangular prism and the cylinder got filled up to a certain height each, the same height say "h" cm.
we know the combined volume of both is 80 cm³, so let's get the volume of each, sum them up to get 80 then.
![\bf \stackrel{\stackrel{\textit{volume of a}}{\textit{rectangular prism}}}{V=Lwh}~~ \begin{cases} L=length\\ w=width\\ h=height\\[-0.5em] \hrulefill\\ L=4\\ w=2\\ \end{cases}~\hspace{2em}\stackrel{\textit{volume of a cylinder}}{V=\pi r^2 h}~~ \begin{cases} r=radius\\ h=height\\[-0.5em] \hrulefill\\ r=1 \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7B%5Cstackrel%7B%5Ctextit%7Bvolume%20of%20a%7D%7D%7B%5Ctextit%7Brectangular%20prism%7D%7D%7D%7BV%3DLwh%7D~~%20%5Cbegin%7Bcases%7D%20L%3Dlength%5C%5C%20w%3Dwidth%5C%5C%20h%3Dheight%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20L%3D4%5C%5C%20w%3D2%5C%5C%20%5Cend%7Bcases%7D~%5Chspace%7B2em%7D%5Cstackrel%7B%5Ctextit%7Bvolume%20of%20a%20cylinder%7D%7D%7BV%3D%5Cpi%20r%5E2%20h%7D~~%20%5Cbegin%7Bcases%7D%20r%3Dradius%5C%5C%20h%3Dheight%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20r%3D1%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D)

What do you mean by that? multiplacation
The answer for this question is (100% correct)
A. 2
Parallel lines have same slope, so first isolate y to get the equation into y=mx+b form.
-2x+3y=2
3y = 2x + 2

Now plug the point (3,4) into y = 2x + b
4 = 2(3) + b
Solves for be
b = -2
So the new equation is y = 2x - 2