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Brrunno [24]
3 years ago
10

find the missing angle measures.

Mathematics
1 answer:
sasho [114]3 years ago
4 0

Answer:

look at the photo I have sent

you wearing a mask right now???

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Match its group with its percentage or mean Using
krok68 [10]

(1)

Mean length of all fish in the sample - \boxed{\sf{\red{6.2}}}

<u>Mean</u> = (Sum of observations)/(Number of observations)

= (12 + 5 + 3 + 5 + 8 + 2 + 10 + 9 + 4 + 4)/(10)

= 62/10

=<em> 6.2</em>

(2)

Mean length of adult fish in the sample - \boxed{\sf{\red{8.75}}}

<u>Mean</u> = (Sum of observations)/(Number of observations)

= (12 + 5 + 8 + 10)/(4)

= 35/4

=<em> 8.75</em>

(3)

Mean length of juvenile fish in the sample - \boxed{\sf{\red{4.5}}}

<u>Mean</u> = (Sum of observations)/(Number of observations)

= (5 + 3 + 2 + 9 + 4 + 4)/(6)

= 27/6

<em>= 4.5</em>

(4)

Percentage of sample that were adult fish - \boxed{\sf{\red{40}}}

<u>Percentage</u> = (No. of adult fishes)/(Total no. of fishes) × 100

% = (4/10) × 100

<em>% = 40</em>

(5)

Percentage of sample that were juvenile fish - \boxed{\sf{\red{60}}}

<u>Percentage</u> = (No. of juvenile fishes)/(Total no. of fishes) × 100

% = (6/10) × 100

<em>% = </em><em>6</em><em>0</em>

(6)

Percentage of sample that were juveniles over 8 inches long - \boxed{\sf{\red{10}}}

<u>Percentage</u> = (No. of juveniles over 8 inches)/(Total no. of fishes) × 100

% = (1/10) × 100

<em>% = </em><em>1</em><em>0</em>

7 0
3 years ago
A frequency distribution for the class level of students in an introductory statistics course is shown. Two students are randoml
Andrews [41]

Answer: \dfrac{21}{410}.

Step-by-step explanation:

Formula : Probability = \dfrac{\text{favorable outcomes}}{\text{Total outcomes}}

From the given frequency distribution for the class level of students in an introductory statistics course, we have

Number of Junior= 12

Number of Senior = 7

Total students = 6+16+12+7 = 41

Probability that the first student obtained is a junior = \dfrac{12}{41}

Probability that the the second student obtained is a senior. =\dfrac{7}{41-1}=\dfrac{7}{40}

Then, the probability that the first student obtained is a junior and the second a senior would be \dfrac{12}{41}\times\dfrac{7}{40}=\dfrac{21}{410}

Hence, the required probability is \dfrac{21}{410}.

8 0
3 years ago
What’s 11 + 9/35 make sure answer is a mixed number
mr_godi [17]

Answer: 11 9/35

Step-by-step explanation: just add the whole number to the fraction.

7 0
3 years ago
Read 2 more answers
Assume that you take a both you fill a tub the halfway point the tub measures 5 feet long 2.1 gallons per minute. There are 7.5
MatroZZZ [7]

Answer:

both? use water for both of them

Step-by-step explanation:

8 0
3 years ago
Find an equation of the line perpendicular to the graph of 15x-3y = 7that passes through the point at 0,
AlekseyPX

Answer:

5y + x = 5c

Step-by-step explanation:

Rewriting the equation, 15x - 3y = 7,

3y = 15x - 7

y = 5x - 7/3. The gradient is 5. The gradient of the perpendicular line is -1/5

The equation of the perpendicular to 15x - 3y = 7 passing through (0,c) is

(y - c)/(x - 0) = -1/5

(y - c)/x = -1/5

y - c = -x/5

y = -x/5 + c

5y = -x + 5c

5y + x = 5c

7 0
3 years ago
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