(1)
Mean length of all fish in the sample - 
<u>Mean</u> = (Sum of observations)/(Number of observations)
= (12 + 5 + 3 + 5 + 8 + 2 + 10 + 9 + 4 + 4)/(10)
= 62/10
=<em> 6.2</em>
(2)
Mean length of adult fish in the sample - 
<u>Mean</u> = (Sum of observations)/(Number of observations)
= (12 + 5 + 8 + 10)/(4)
= 35/4
=<em> 8.75</em>
(3)
Mean length of juvenile fish in the sample - 
<u>Mean</u> = (Sum of observations)/(Number of observations)
= (5 + 3 + 2 + 9 + 4 + 4)/(6)
= 27/6
<em>= 4.5</em>
(4)
Percentage of sample that were adult fish - 
<u>Percentage</u> = (No. of adult fishes)/(Total no. of fishes) × 100
% = (4/10) × 100
<em>% = 40</em>
(5)
Percentage of sample that were juvenile fish - 
<u>Percentage</u> = (No. of juvenile fishes)/(Total no. of fishes) × 100
% = (6/10) × 100
<em>% = </em><em>6</em><em>0</em>
(6)
Percentage of sample that were juveniles over 8 inches long - 
<u>Percentage</u> = (No. of juveniles over 8 inches)/(Total no. of fishes) × 100
% = (1/10) × 100
<em>% = </em><em>1</em><em>0</em>
Answer:
.
Step-by-step explanation:
Formula : Probability = 
From the given frequency distribution for the class level of students in an introductory statistics course, we have
Number of Junior= 12
Number of Senior = 7
Total students = 6+16+12+7 = 41
Probability that the first student obtained is a junior = 
Probability that the the second student obtained is a senior. 
Then, the probability that the first student obtained is a junior and the second a senior would be 
Hence, the required probability is
.
Answer: 11 9/35
Step-by-step explanation: just add the whole number to the fraction.
Answer:
both? use water for both of them
Step-by-step explanation:
Answer:
5y + x = 5c
Step-by-step explanation:
Rewriting the equation, 15x - 3y = 7,
3y = 15x - 7
y = 5x - 7/3. The gradient is 5. The gradient of the perpendicular line is -1/5
The equation of the perpendicular to 15x - 3y = 7 passing through (0,c) is
(y - c)/(x - 0) = -1/5
(y - c)/x = -1/5
y - c = -x/5
y = -x/5 + c
5y = -x + 5c
5y + x = 5c