The question requires calculating the perimeter of the rectangular r ug
The equation which represent the situation is 113/2 = 6x + 34/4 and length is 8 inches and width is 20 1/4 inches
Given:
let
length of the rectangular r ug = x inches
Width of a rectangular r ug = <em>(2x + 4 1/4) inches</em>
Perimeter of the r ug = 56 1/2 inches
<em>Perimeter of the r ug = 2(length + width)</em>
56 1/2 = 2{x + (2x + 4 1/4)
113/2 = 2(x + 2x + 17/4)
113/2 = 2(3x + 17/4)
113/2 = 6x + 34/4
113/2 - 34/4 = 6x
(226-34) / 4 = 6x
192/4 = 6x
48 = 6x
divide both sides by 6
x = 48/6
x = 8 inches
So,
length of the rectangular r ug = x inches
= 8 inches
Width of a rectangular r ug = (2x + 4 1/4) inches
= 2(8) + 4 1/4
= 16 + 4 1/4
= 20 1/4 inches
Therefore, the equation which represent the situation is 113/2 = 6x + 34/4 and length is 8 inches and width is 20 1/4 inches
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