How many solutions does the following equation have?
1 answer:
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Answer:
No graph so we'll use the quadratic formula
x^2+x-4=0
a = 1
b = 1
c = -4
x = -1 +- sqr root (1^2 - 4 * 1 * -4) / 2
x = (-1 +- sqr root (1 +16) ) / 2
x1 = (-1 + sqr root (17)) / 2
x2 = (-1 - sqr root (17)) / 2
Step-by-step explanation:
Answer:
The total amount of soils that planter will hold to it is 590.45 inches³
Step-by-step explanation:
Given as :
The radius of the cone shape planter = r = 6.8 inches
The height of the cone shape planter = h = 12.2 inches
Let The total amount of soils that will hold to it = x cubic inches
Now, According to question
The total amount of soils that planter will hold to it = The volume of the cone
∵ The volume of cone = v = r² h
where r is the radius
And h is the height
So, The total amount of soils that planter will hold to it = r² h
or, x = ×
× r² × h
or, x = × 3.14 × (6.8)² inches × 12.2 inches
or, x = × 3.14 × 564.128 inches³
or, x = × 1771.361 inches³
or, x = inches³
∴ x = 590.45 inches³
So, The total amount of soils that planter will hold to it = x = 590.45 inches³
Hence, The total amount of soils that planter will hold to it is 590.45 inches³ . Answer