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yaroslaw [1]
3 years ago
10

What is true of angles c and d?

Mathematics
2 answers:
MrMuchimi3 years ago
5 0
The answer is D, both angles = 180 degrees which means they are complementary.
Iteru [2.4K]3 years ago
3 0

Answer:

<u>D) The two angles are complementary</u>

Step-by-step explanation:

\dashrightarrow \: { \tt{c + d = 180 \degree}}

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For science class, a student recorded the high and low temperatures, in Fahrenheit, over a ten day period in September. The data
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Thee correlation factor formula for two variables is 
(r) =[ nΣxy – (Σx)(Σy) / Sqrt([nΣx^2 – (Σx)^2][nΣy^2 – (Σy)^2])].

A). as per the formula the correlation factor for the given  data is 0.94.

B). the month of September has the highest correlation as 0.94 is much closer to 1 than 0.89.( note: 1 denotes the perfect correlation and 0 denotes no correlation at all)

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Mike is about 1.6 meters tall. A rock is about 2.3 x 10-² meters tall.
yawa3891 [41]

Answer:

The answer to the equation should be C

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3 years ago
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Solve the equation by graphing. If exact roots cannot be found, state the consecutive integers between which the roots are locat
eimsori [14]

Answer:

There are NO real roots for this equation. The only roots have imaginary parts and therefore cannot be represented on the real x-axis.

Step-by-step explanation:

We notice that the expression on the left of the equation is a quadratic with leading term 2x^2, which means that its graph is that of a parabola with branches going up.

Therefore, there can be three different situations:

1) if its vertex is ON the x axis, there would be one unique real solution (root) to the equation.

2) if its vertex is below the x-axis, the parabola's branches are forced to cross it at two locations, giving then two real solutions (roots) to the equation.

3) if its vertex is above the x-axis, it will have NO real solutions (roots) but only non-real ones.

So we proceed to examine the vertex's location, which is also a great way to decide on which set of points to use in order to plot its graph efficiently.

We recall that the x-position of the vertex for a quadratic function of the form  f(x)=ax^2+bx+c is given by the expression:

x_v=\frac{-b}{2a}

Since in our case a=2 and b=-3, we get that the x-position of the vertex is:

x_v=\frac{-b}{2a}\\x_v=\frac{-(-3)}{2(2)}\\x_v=\frac{3}{4}

Now we can find the y-value of the vertex by evaluating this quadratic expression for x = 3/4:

y_v=f(\frac{3}{4})=2( \frac{3}{4})^2-3(\frac{3}{4})+4\\f(\frac{3}{4})=2( \frac{9}{16})-\frac{9}{4}+4\\f(\frac{3}{4})=\frac{9}{8}-\frac{9}{4}+4\\f(\frac{3}{4})=\frac{9}{8}-\frac{18}{8}+\frac{32}{8}\\f(\frac{3}{4})=\frac{23}{8}

This is a positive value for y, therefore we are in the situation where there is NO x-axis crossing of the parabola's graph, and therefore no real roots.

We can though estimate a few more points of the parabola's graph in order to complete the graph as requested in the problem. For such we select a couple of x-values to the right of the vertex, and a couple to the right so we can draw the branches. For example: x = 1, and x = 2 to the right; and x = 0 and x = -1 to the left of the vertex:

f(-1) = 2(-1)^2-3(-1)+4= 2+3+4=9\\f(0)=2(0)^2-3(0)+4=0+0+4=4\\f(1)=2(1)^2-3(-1)+4=2-3+4=3\\f(2)=2(2)^2-3(2)+4=8-6+4=6

See the graph produced in the attached image.

4 0
3 years ago
Factor 6d^2 – 21d.<br> The factored polynomial is
lara [203]
Factor 3d out of 6d^2 -21d
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3 0
3 years ago
Find the area of the shape shown below.
erastovalidia [21]

Answer:

10

Step-by-step explanation:

2x2=4

1x2=2

2x2=4

4+2+4=10

write this down if u need to show work

8 0
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