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Reika [66]
3 years ago
8

The bakery packages 8 of the chocolate spheres into a box .If the density of the chocolate is 1.308 g/cm3 ,what is the total mas

s of the chocolate in the box
Mathematics
1 answer:
DanielleElmas [232]3 years ago
5 0

Answer:

m=DxV. 1.308x8= 10.464

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A. 7 1/6

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10 3/4 * 2/3=

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86/12 = 7 2/12 = 7 1/6

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If the length of a diagonal of a square is a, what is the length of its side
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The same as the diagonal of a square.
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Sarah and Jake timed themselves while running. Who ran at a faster speed?
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Write the slope-intercept form of the equation of each line. identify the slopes y-intercept.
MrRa [10]

Answer:

Step-by-step explanation:

1) y intercept is 0

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4 0
3 years ago
Read 2 more answers
Can anyone explain to me how to do this question ? ty !!​
julia-pushkina [17]

Step-by-step explanation:

use a little imagination.

the whole thing is a combination of churches and half- circles.

and you know the formula for the area of a circle ?

A = pi×r²

so, the only difficulty is to find the circles and then the radius of each involved circle.

when you look at the picture, the shaded area is almost identical to the lower half of the main circle.

2 bumps "look" over into the other side, but one equally sized bump is removed from this lower half.

so, as a first step we will calculate the area of the lower half of the main circle.

the diameter is 24 m, so the radius is half of that : 12m

the area of the large circle is therefore

pi×12² = 144×pi m²

since we only need the (lower) half, we divide this by 2 :

144×pi / 2 = 72×pi m²

the bumps up and down are actually half-circles too. just of smaller circles.

since AB = BC = CD, we know each of these lines are 1/3 of the main diameter AD.

so, the diameter of the smaller circles is 24/3 = 8 m

and their radius is half of that = 8/2 = 4m

the area of such a small circle is therefore

As = pi×4² = 16×pi m²

and a small half-circle area is then

16×pi / 2 = 8×pi m²

so, for the full shaded area I need to take the large half-circle and add 2 small half-circles, and then subtract 1 small half-circle.

so, in total I only need to add 1 small half-circle.

Ashaded = 72×pi + 8×pi = 80×pi m²

5 0
3 years ago
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