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SCORPION-xisa [38]
3 years ago
7

Evaluate g(-4) when g(b) = - 4(12.5b - 2) Can someone help please?

Mathematics
1 answer:
Stolb23 [73]3 years ago
3 0
The answer to your problem is 50b+8

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Please help me im stressing :((
Olegator [25]

9514 1404 393

Answer:

  • wrong: -2x² -x² ⇒ -2x²
  • correct: x³ -3x² +6

Step-by-step explanation:

The point of these "what was done wrong" exercises is to see if you know what the correct steps look like.

On line 2, Danielle correctly distributed the minus sign to eliminate the second set of parentheses. (There is often a problem with minus signs and parentheses, so it is nice to see it done correctly.)

On line 3, the two x² terms are incorrectly combined. It looks as though Danielle simply dropped the -x² term because it disappeared without changing the coefficient of x² from -2x². The correct sum of those terms is ...

  -2x² -x² = -3x²

so the correct work on line 3 is ...

  x³ -3x² +6

7 0
3 years ago
Is 3.113x10^22 smaller or bigger than 2.113x10^23
weqwewe [10]
<span>2.113x10^23 is bigger since it has one more 'unit' (i forgot the term for ones, tens, hundreds, and so on) compared to 3.113 x 10^22</span>
7 0
3 years ago
I need help wit this
balu736 [363]
I hope this helps you

5 0
3 years ago
Formulate the recursive formula for the following geometric sequence.<br> {-16, 4, -1, ...}
CaHeK987 [17]
4 / -16 = -1/4. (also -1/4 = -1/4).

The general form of the sequence is:
a, ar, ar^2, ar^3....

Where r is the ratio: 1/4, and a is first term: -16.

You can see each term is just ar^n where n is the term number, starting where the first term n=0.

So the general formula would be:

-16(-1/4)^n
8 0
3 years ago
10. Find the real-number root. 3√0.001
Zepler [3.9K]
I hope this helps you




3 square root of (0,1)^3



(0,1)^3/3


0,1
6 0
3 years ago
Read 2 more answers
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