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2 years ago

Find the measure of 4

Mathematics

2 answers:

IceJOKER [234]2 years ago

8 0

<em><u>ᎪꪀsωꫀᏒ</u></em>

angle 4 = 147

Step-by-step explanation:

angle 4 + 33 = 180

angle 4 = 180-33

angle 4 = 147

schepotkina [342]2 years ago

5 0

Answer:

147º

Step-by-step explanation:

180-33=147

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Which point is on the line that passes through (0,6) and is parallel to the given line? plzz helppp!

Grace [21]

Points on given line = (-12,-2) and (0,-4) because you can see them on the graph. Then draw a parallel line thru (0,6)

To get from (0,-4) to (0,6) your x stays constant and your y coordinate increased by 10. So your new point will do the same in relation to (-12,-2) the x will stay constant at -12 and your y will increase by 10 to +8.

So the answer is A (-12,8)

You can check this because parallel lines have the same slope so

y2-y1/x2-x1 should be equal for both lines.

Line 1: -4 - (-2) / 0 - (-12) = -2/12 = -1/6

Line 2: 6 - 8 / 0 - (-12) = -2/12 = -1/6

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3 years ago

List the term(s) in the following expression:<br> 2x2–5xy + 8y4

eduard

Answer:

−

Step-by-step explanation:

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2 years ago

Determine whether the given value is a solution of the equation: x + 15 = 10; x=5 *

kobusy [5.1K]

Answer:

It is not correct, x = -5

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

Select all possible values for x in the equation x^3=375?

Helga [31]

<h2>Hello!</h2>

The answers are:

The possible values for x in the equation, are:

First option, $5\sqrt[3]{3}$

Second option, $\sqrt[3]{375}$

To solve the problem, we need to remember the following properties of the exponents and roots:

$a\sqrt[n]{b}=\sqrt[n]{a^{n}*b} \\\\\sqrt[n]{a^{m} }=a^{\frac{m}{n}}\\\\(a^{b})^{c}=a^{b*c}$

Then, we are given the expression:

$x^{3}=375$

So, finding "x", we have:

$x^{3}=375\\\\(x^{3})^{\frac{1}{3} } =(375)^{\frac{1}{3}}\\\\x=\sqrt[3]{375}=\sqrt[3]{125*3}=\sqrt[3]{125}*\sqrt[3]{3}=5\sqrt[3]{3}$

Hence, the possible values for x in the equation, are:

First option, $5\sqrt[3]{3}$

Second option, $\sqrt[3]{375}$

Have a nice day!

7 0

3 years ago

In the following exercises, solve

yKpoI14uk [10]

Answer:

When the volume of a gas in a container varies inversely with the pressure on the gas and a container of nitrogen has a volume of 29.5 litres with 2000 psi. So, if the tank has a 14.7 psi pressure, then the volume of the tank would be 4013.6 litres.

Step-by-step explanation:

The volume of a gas in a container varies inversely with the pressure on the gas. If a container of nitrogen has a volume of litres with psi, what is the volume if the tank has a psi pressure.

Calculate the volume to the nearest whole number.

Use the given values and calculate the proportionality constant as well as required solution.

Step 1 of 2

Write the inversely proportionality relation between the volume and pressure of a gas in container.

$v \propto \frac{1}{p}$

Where volume is represented by v and pressure is represented by p.

Remove the proportionality and place a constant say k.

$v=\frac{k}{p}$

Substitute the given values of nitrogen that v=29.5 and

p=2000 and calculate the value of k from above equation.

$\begin{aligned}&29.5=\frac{k}{2000} \\&\Rightarrow k=29.5 \times 2000 \\&\Rightarrow k=59000\end{aligned}$

Step 2 of 2

Substitute the value p=14.7 and above calculated k value in the equation

$\begin{aligned}&v=\frac{k}{p} . \\&v=\frac{59000}{14.7} \\&\Rightarrow v=4013.6\end{aligned}$

7 0

1 year ago