Point P is the incenter of triangle ABC, PZ = 7 units, and PA = 12 units.
1 answer:
The complete question is
"Point P is the incenter of triangle ABC, PZ = 7 units, and PA = 12 units.
The radius of the incircle centered at point P is ? units."
The radius of the incircle centered at point P is 7 units.
We are given that point P is the incenter of the triangle, and is the center point of the incircle of the triangle.
<h3>What is incircle?</h3>The incircle is defined as the largest circle that can be made in a triangle and is tangent to each side of the triangle.
Here, The radius of the circle is going to be a perpendicular line from point P to any side of the triangle.
In the triangle ,
PZ = PY = PX,
Each measure of value is equal to the radius of the circle.
Therefore, we already know that PZ = 7 units making the radius, r = 7 units.
Learn more about incircle;
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Step-by-step explanation:
Take the first derivative
Set the derivative equal to 0.
or
For any number less than -1, the derivative function will have a Positve number thus a Positve slope for f(x).
For any number, between -1 and 1, the derivative slope will have a negative , thus a negative slope.
Since we are going to Positve to negative slope, we have a local max at x=-1
Plug in -1 for x into the original function
So the local max is 2 and occurs at x=-1,
For any number greater than 1, we have a Positve number for the derivative function we have a Positve slope.
Since we are going to decreasing to increasing, we have minimum at x=1,
Plug in 1 for x into original function
So the local min occurs at -2, at x=1