Answer:
There are 15 total Carbon Atoms
there are 5 groups of 3
5(C3)
5x3 = 15
C
I have had this question on a test before!! Hope this helps
Answer:
12.26%
Explanation:
MM K = 39.1 g/mol
MM K2CO3 . 10H2O = 2x39.1 + 12.01 + 3 x 15.99 + 10 x 18.02= 318.38 g/mol
% by weight = (MM K/MM K2CO3.10H2O ) x 100= (39.1/318.8) x 100=12.26 %
