144 miles per hours into feet per second
1 answer:
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Answer: Angle 2 = 47 degree
Explanation:
Proof that triangle ACB ~ triangle CBD
Angle ABC = Angle CBD (same angle)
If one pair of the angle is the same then the other pair should also be equal because both the triangle are Isosceles.
=> angle ACD = Angle CDB
Therefore, triangle ACB ~ triangle CBD (AA)
=> angle C = Angle A
But angle A = 47 degree
Therefore, Angle C = Angle 2 = 47 degree
Explanation:
Proof that triangle ACB ~ triangle CBD
Angle ABC = Angle CBD (same angle)
If one pair of the angle is the same then the other pair should also be equal because both the triangle are Isosceles.
=> angle ACD = Angle CDB
Therefore, triangle ACB ~ triangle CBD (AA)
=> angle C = Angle A
But angle A = 47 degree
Therefore, Angle C = Angle 2 = 47 degree
Answer:
The height of the tree=8.42 m
Step-by-step explanation:
We are given that
Height of Joshua, h=1.45 m
Length of tree's shadow, L=31.65 m
Distance between tree and Joshua=26.2 m
We have to find the height of the tree.
BC=26.2 m
BD=31.65m
CD=BD-BC
CD=31.65-26.2=5.45 m
EC=1.45 m
All right triangles are similar .When two triangles are similar then the ratio of their corresponding sides are equal.
Substitute the values
Hence, the height of the tree=8.42 m
