Answer:
The answer to your question is A.
Step-by-step explanation:
Remember that
1 yard = 3 feet
so
10 ft=10/3 yd
Convert to a mixed number
10/3=9/3+1/3=3 1/3 yd
<h2>the answer is option A</h2>
First, distribute 8 to both k and -4, and 8k to both 7k and 8
8(k - 4) = 8k - 32
8k(7k + 8) = 56k² + 64k
Combine like terms
56k² + (64k + 8k) - 32
56k² + 72k - 32
56k² + 72k - 32 is your answer
hope this helps
Since
and by inscribed angle theorem,
![\angle PAB \cong \angle PYB;\\\angle QAB \cong \angle QXB](https://tex.z-dn.net/?f=%20%5Cangle%20PAB%20%5Ccong%20%5Cangle%20PYB%3B%5C%5C%3C%2Fp%3E%3Cp%3E%5Cangle%20QAB%20%5Ccong%20%5Cangle%20QXB)
By transitivity,
![\implies \angle QXB \cong \angle PYB\\\mathrm {or}\: \angle PXQ \cong \angle QYP\\\implies \text{PQXY is cyclic}](https://tex.z-dn.net/?f=%20%5Cimplies%20%5Cangle%20QXB%20%5Ccong%20%5Cangle%20PYB%5C%5C%3C%2Fp%3E%3Cp%3E%5Cmathrm%20%7Bor%7D%5C%3A%20%5Cangle%20PXQ%20%5Ccong%20%5Cangle%20QYP%5C%5C%3C%2Fp%3E%3Cp%3E%5Cimplies%20%5Ctext%7BPQXY%20is%20cyclic%7D)
This follows from the converse of the theorem that angles subtended on a circle by a chord of fixed length are equal. Here, chord $PQ$ of the circle passing through $PQXY$ subtends equal angles at points $X$ and $Y$ on the circle.